---
title: "A uniform meter stick has a mass of \\( 45.0 \\) \\( \\text{g} \\) placed at the \\( 20 \\) \\( \\text{cm} \\) mark. If a pivot is placed at the \\( 42.5 \\) \\( \\text{cm} \\) mark and the meter stick remains horizontal in static equilibrium, what is the mass of the meter stick?"
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url: "https://nerd-notes.com/ubq/104281/"
date_modified: "2025-10-31T08:19:00+00:00"
---

# A uniform meter stick has a mass of \( 45.0 \) \( \text{g} \) placed at the \( 20 \) \( \text{cm} \) mark. If a pivot is placed at the \( 42.5 \) \( \text{cm} \) mark and the meter stick remains horizontal in static equilibrium, what is the mass of the meter stick?

A uniform meter stick has a mass of \( 45.0 \) \( \text{g} \) placed at the \( 20 \) \( \text{cm} \) mark. If a pivot is placed at the \( 42.5 \) \( \text{cm} \) mark and the meter stick remains horizontal in static equilibrium, what is the mass of the meter stick?

![Diagram](https://nerd-notes.com/wp-content/uploads/2025/10/A-uniform-meter-stick-static-equilibirum-torque-1.png)

- **A.** \( 45.0 \) \( \text{g} \)
- **B.** \( 72.0 \) \( \text{g} \)
- **C.** \( 120.0 \) \( \text{g} \)
- **D.** \( 135.0 \) \( \text{g} \)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/104281/*