---
title: "A \\(350\\ \\text{g}\\) ball is attached to the end of a thin, uniform rod of mass \\(500\\ \\text{g}\\) and length \\(1.2\\ \\text{m}\\). The system is rotated in a horizontal circle about the opposite end of the rod. Calculate the moment of inertia of the system about the axis of rotation.  Hint: the moment of inertia of a thin rod about the end of the rod is \\(I = \\tfrac{1}{3} m L^2\\)."
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url: "https://nerd-notes.com/ubq/104414/"
date_modified: "2025-11-02T14:10:52+00:00"
---

# A \(350\ \text{g}\) ball is attached to the end of a thin, uniform rod of mass \(500\ \text{g}\) and length \(1.2\ \text{m}\). The system is rotated in a horizontal circle about the opposite end of the rod. Calculate the moment of inertia of the system about the axis of rotation.  Hint: the moment of inertia of a thin rod about the end of the rod is \(I = \tfrac{1}{3} m L^2\).

A \(350\ \text{g}\) ball is attached to the end of a thin, uniform rod of mass \(500\ \text{g}\) and length \(1.2\ \text{m}\). The system is rotated in a horizontal circle about the opposite end of the rod. Calculate the moment of inertia of the system about the axis of rotation. Hint: the moment of inertia of a thin rod about the end of the rod is \(I = \tfrac{1}{3} m L^2\).

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/104414/*