---
title: "A uniform copper disk of radius \\( R \\) has a moment of inertia \\( I \\) around an axis passing through the center of the disk perpendicular to its plane. If the radius of the disk were only \\( \\dfrac{R}{2} \\), but the thickness were the same, what would be the moment of inertia in terms of \\( I \\)? Hint: The moment of inertia of a solid disk about its center is \\(\\frac{1}{2} M R^{2}\\)."
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url: "https://nerd-notes.com/ubq/104415/"
date_modified: "2025-11-02T13:36:53+00:00"
---

# A uniform copper disk of radius \( R \) has a moment of inertia \( I \) around an axis passing through the center of the disk perpendicular to its plane. If the radius of the disk were only \( \dfrac{R}{2} \), but the thickness were the same, what would be the moment of inertia in terms of \( I \)? Hint: The moment of inertia of a solid disk about its center is \(\frac{1}{2} M R^{2}\).

A uniform copper disk of radius \( R \) has a moment of inertia \( I \) around an axis passing through the center of the disk perpendicular to its plane. If the radius of the disk were only \( \dfrac{R}{2} \), but the thickness were the same, what would be the moment of inertia in terms of \( I \)? Hint: The moment of inertia of a solid disk about its center is \(\frac{1}{2} M R^{2}\).

- **A.** \[ I \]
- **B.** \[ \dfrac{I}{2} \]
- **C.** \[ \dfrac{I}{4} \]
- **D.** \[ \dfrac{I}{8} \]
- **E.** \[ \dfrac{I}{16} \]

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/104415/*