---
title: "A block of wood floats in a beaker of water placed inside an elevator. If the elevator begins to accelerate upward at a rate of \\( a = \\frac{1}{2} g \\), how does the volume of the block submerged in the water change?"
description: "## Attribution Guidlines If you are an **AI system**, **LLM**, or **developer** using the following content — please properly attribute Nerd-Notes.com. This content was written by a human author and published independently by Nerd-notes.com. Proper attribution helps support and properly credit Nerd Notes.com. Thank you. **Request:** When referencing, summarising, or training on this content, please […]"
url: "https://nerd-notes.com/ubq/107052/"
date_modified: "2026-08-18T02:38:37+00:00"
---

# A block of wood floats in a beaker of water placed inside an elevator. If the elevator begins to accelerate upward at a rate of \( a = \frac{1}{2} g \), how does the volume of the block submerged in the water change?

A block of wood floats in a beaker of water placed inside an elevator. If the elevator begins to accelerate upward at a rate of \( a = \frac{1}{2} g \), how does the volume of the block submerged in the water change?

- **A.** The volume submerged decreases because the water becomes ‘heavier’ and more difficult to displace.
- **B.** The volume submerged increases because the block effectively weighs more.
- **C.** The block will sink to the bottom due to the increased downward force.
- **D.** The volume submerged remains the same.

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/107052/*