---
title: "In a hydraulic system, Piston A has an area of \\( 0.002 \\) \\( \\text{m}^2 \\) and Piston B has an area of \\( 0.1 \\) \\( \\text{m}^2 \\). If a \\( 40 \\) \\( \\text{N} \\) force is applied to Piston A, what is the maximum mass (using \\( g = 10 \\) \\( \\text{m/s}^2 \\)) that can be supported by Piston B at the same vertical height?"
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url: "https://nerd-notes.com/ubq/107127/"
date_modified: "2026-08-18T02:38:23+00:00"
---

# In a hydraulic system, Piston A has an area of \( 0.002 \) \( \text{m}^2 \) and Piston B has an area of \( 0.1 \) \( \text{m}^2 \). If a \( 40 \) \( \text{N} \) force is applied to Piston A, what is the maximum mass (using \( g = 10 \) \( \text{m/s}^2 \)) that can be supported by Piston B at the same vertical height?

In a hydraulic system, Piston A has an area of \( 0.002 \) \( \text{m}^2 \) and Piston B has an area of \( 0.1 \) \( \text{m}^2 \). If a \( 40 \) \( \text{N} \) force is applied to Piston A, what is the maximum mass (using \( g = 10 \) \( \text{m/s}^2 \)) that can be supported by Piston B at the same vertical height?

- **A.** \( 200 \) \( \text{kg} \)
- **B.** \( 20 \) \( \text{kg} \)
- **C.** \( 0.8 \) \( \text{kg} \)
- **D.** \( 2000 \) \( \text{kg} \)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/107127/*