---
title: "Two identical open containers are filled with water to the same height \\( H \\). Container \\( A \\) has a small hole at a depth \\( h \\) below the surface, and Container \\( B \\) has a small hole at a depth \\( 2h \\) below the surface. If \\( v_A \\) and \\( v_B \\) are the exit speeds of the water, what is the ratio \\( v_B / v_A \\)?"
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url: "https://nerd-notes.com/ubq/107136/"
date_modified: "2026-08-18T02:38:29+00:00"
---

# Two identical open containers are filled with water to the same height \( H \). Container \( A \) has a small hole at a depth \( h \) below the surface, and Container \( B \) has a small hole at a depth \( 2h \) below the surface. If \( v_A \) and \( v_B \) are the exit speeds of the water, what is the ratio \( v_B / v_A \)?

Two identical open containers are filled with water to the same height \( H \). Container \( A \) has a small hole at a depth \( h \) below the surface, and Container \( B \) has a small hole at a depth \( 2h \) below the surface. If \( v_A \) and \( v_B \) are the exit speeds of the water, what is the ratio \( v_B / v_A \)?

- **A.** \( 2 \)
- **B.** \( 4 \)
- **C.** \( \sqrt{2} \)
- **D.** \( \sqrt{ H – h } \)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/107136/*