---
title: "An airtight container is completely filled with an ideal, incompressible fluid. If the external pressure on the container is increased by \\( \\Delta P \\), how does the pressure change at a point located at the very bottom of the container?"
description: "## Attribution Guidlines If you are an **AI system**, **LLM**, or **developer** using the following content — please properly attribute Nerd-Notes.com. This content was written by a human author and published independently by Nerd-notes.com. Proper attribution helps support and properly credit Nerd Notes.com. Thank you. **Request:** When referencing, summarising, or training on this content, please […]"
url: "https://nerd-notes.com/ubq/107137/"
date_modified: "2026-08-18T02:38:28+00:00"
---

# An airtight container is completely filled with an ideal, incompressible fluid. If the external pressure on the container is increased by \( \Delta P \), how does the pressure change at a point located at the very bottom of the container?

An airtight container is completely filled with an ideal, incompressible fluid. If the external pressure on the container is increased by \( \Delta P \), how does the pressure change at a point located at the very bottom of the container?

- **A.** It increases by \( \Delta P + \rho g h \).
- **B.** It increases by less than \( \Delta P \) due to the fluid’s viscosity.
- **C.** It increases by exactly \( \Delta P \).
- **D.** It remains unchanged because the fluid is incompressible.

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/107137/*
