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title: "A sinusoidal graph of position versus time for a weight on a string undergoing simple harmonic motion is provided. The vertical axis is labeled X (m) and the horizontal axis is labeled t (s). The origin is at the intersection of the axes. Tick marks on the time axis are at \\( 0.10 \\) \\( \\text{s} \\), \\( 0.30 \\) \\( \\text{s} \\), \\( 0.50 \\) \\( \\text{s} \\), and \\( 0.70 \\) \\( \\text{s} \\). The peak displacement on the vertical axis is \\( 0.15 \\) \\( \\text{m} \\) above zero and \\( -0.15 \\) \\( \\text{m} \\) below zero. The sine curve starts at the origin at \\( t = 0 \\), reaches a positive maximum near \\( t = 0.10 \\) \\( \\text{s} \\), crosses zero at \\( t = 0.20 \\) \\( \\text{s} \\), reaches a negative minimum near \\( t = 0.30 \\) \\( \\text{s} \\), and continues periodically. Using this graph, answer the following."
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url: "https://nerd-notes.com/ubq/108975/"
date_modified: "2026-08-18T02:38:07+00:00"
---

# A sinusoidal graph of position versus time for a weight on a string undergoing simple harmonic motion is provided. The vertical axis is labeled X (m) and the horizontal axis is labeled t (s). The origin is at the intersection of the axes. Tick marks on the time axis are at \( 0.10 \) \( \text{s} \), \( 0.30 \) \( \text{s} \), \( 0.50 \) \( \text{s} \), and \( 0.70 \) \( \text{s} \). The peak displacement on the vertical axis is \( 0.15 \) \( \text{m} \) above zero and \( -0.15 \) \( \text{m} \) below zero. The sine curve starts at the origin at \( t = 0 \), reaches a positive maximum near \( t = 0.10 \) \( \text{s} \), crosses zero at \( t = 0.20 \) \( \text{s} \), reaches a negative minimum near \( t = 0.30 \) \( \text{s} \), and continues periodically. Using this graph, answer the following.

A sinusoidal graph of position versus time for a weight on a string undergoing simple harmonic motion is provided. The vertical axis is labeled X (m) and the horizontal axis is labeled t (s). The origin is at the intersection of the axes. Tick marks on the time axis are at \( 0.10 \) \( \text{s} \), \( 0.30 \) \( \text{s} \), \( 0.50 \) \( \text{s} \), and \( 0.70 \) \( \text{s} \). The peak displacement on the vertical axis is \( 0.15 \) \( \text{m} \) above zero and \( -0.15 \) \( \text{m} \) below zero. The sine curve starts at the origin at \( t = 0 \), reaches a positive maximum near \( t = 0.10 \) \( \text{s} \), crosses zero at \( t = 0.20 \) \( \text{s} \), reaches a negative minimum near \( t = 0.30 \) \( \text{s} \), and continues periodically. Using this graph, answer the following.

**Part a)** Determine the amplitude of the motion from the graph. *(3 points)*

**Part b)** Determine the period of the motion from the graph. *(3 points)*

**Part c)** Calculate the frequency of the motion. *(3 points)*

**Part d)** On the graph, label a point where the velocity is zero. *(3 points)*

**Part e)** On the graph, label the points where the acceleration is maximum and where it is minimum. *(3 points)*

**Part f)** On the graph, indicate the points where the kinetic energy reaches its maximum value. *(3 points)*

**Part g)** On the graph, indicate the points where the potential energy is greatest. *(3 points)*


*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/108975/*
