---
title: "A motor-driven conveyor belt moves a crate of mass \\(M\\) at a constant speed \\(v\\) along a horizontal track. The coefficient of kinetic friction between the crate and the track is \\(\\mu\\). To maintain this constant speed, the motor must supply a power \\(P_1\\). The crate is replaced with a larger crate of mass \\(2M\\) and the speed of the conveyor belt is increased to a constant speed of \\(3v\\). If the coefficient of kinetic friction remains the same, which of the following is the best estimate for the power \\(P_2\\) now supplied by the motor?"
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url: "https://nerd-notes.com/ubq/110109/"
date_modified: "2026-03-27T05:26:19+00:00"
---

# A motor-driven conveyor belt moves a crate of mass \(M\) at a constant speed \(v\) along a horizontal track. The coefficient of kinetic friction between the crate and the track is \(\mu\). To maintain this constant speed, the motor must supply a power \(P_1\). The crate is replaced with a larger crate of mass \(2M\) and the speed of the conveyor belt is increased to a constant speed of \(3v\). If the coefficient of kinetic friction remains the same, which of the following is the best estimate for the power \(P_2\) now supplied by the motor?

A motor-driven conveyor belt moves a crate of mass \(M\) at a constant speed \(v\) along a horizontal track. The coefficient of kinetic friction between the crate and the track is \(\mu\). To maintain this constant speed, the motor must supply a power \(P_1\). The crate is replaced with a larger crate of mass \(2M\) and the speed of the conveyor belt is increased to a constant speed of \(3v\). If the coefficient of kinetic friction remains the same, which of the following is the best estimate for the power \(P_2\) now supplied by the motor?

- **A.** \(1.5 P_1\)
- **B.** \(3 P_1\)
- **C.** \(5 P_1\)
- **D.** \(6 P_1\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/110109/*