---
title: "The graph shows the spectral intensity of radiation emitted by a distant star as a function of wavelength \\(\\lambda\\). Wien’s displacement constant is \\(b = 2.90 \\times 10^{-3} \\text{ m}\\cdot\\text{K}\\). Based on the peak emission wavelength shown in the graph, what is the approximate surface temperature of the star?"
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url: "https://nerd-notes.com/ubq/117369/"
date_modified: "2026-08-04T06:51:59+00:00"
---

# The graph shows the spectral intensity of radiation emitted by a distant star as a function of wavelength \(\lambda\). Wien’s displacement constant is \(b = 2.90 \times 10^{-3} \text{ m}\cdot\text{K}\). Based on the peak emission wavelength shown in the graph, what is the approximate surface temperature of the star?

The graph shows the spectral intensity of radiation emitted by a distant star as a function of wavelength \(\lambda\). Wien's displacement constant is \(b = 2.90 \times 10^{-3} \text{ m}\cdot\text{K}\). Based on the peak emission wavelength shown in the graph, what is the approximate surface temperature of the star?

![A graph showing spectral intensity on the vertical axis versus wavelength lambda in nanometers on the horizontal axis. The horizontal axis ranges from 0 to 1200 nm, with tick marks at 0, 200, 400, 500, 600, 800, 1000, and 1200 nm. A smooth curve starts at the origin, rises sharply to a single maximum peak precisely at lambda = 500 nm, and then gradually decays toward zero at long wavelengths. A vertical dashed line extends down from the peak at 500 nm to the horizontal axis. No other labels, lines, text, or axes appear.](https://nerd-notes.com/wp-content/uploads/ubq-frq-generated/stem-fig-1-1785826319-todL6b.jpg)

- **A.** \(1450 \text{ K}\)
- **B.** \(2900 \text{ K}\)
- **C.** \(5000 \text{ K}\)
- **D.** \(5800 \text{ K}\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/117369/*