---
title: "A monochromatic beam of light traveling in Medium 1 with index of refraction \\(n_1\\) enters Medium 2 with index of refraction \\(n_2\\), where \\(n_1 > n_2\\). The angle of incidence relative to the normal is \\(\\theta_1\\) and the angle of refraction is \\(\\theta_2\\). Which of the following graphs best represents \\(\\sin\\theta_2\\) as a function of \\(\\sin\\theta_1\\) for incident angles from \\(0^\\circ\\) up to \\(90^\\circ\\)?"
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url: "https://nerd-notes.com/ubq/117502/"
date_modified: "2026-08-04T06:52:23+00:00"
---

# A monochromatic beam of light traveling in Medium 1 with index of refraction \(n_1\) enters Medium 2 with index of refraction \(n_2\), where \(n_1 > n_2\). The angle of incidence relative to the normal is \(\theta_1\) and the angle of refraction is \(\theta_2\). Which of the following graphs best represents \(\sin\theta_2\) as a function of \(\sin\theta_1\) for incident angles from \(0^\circ\) up to \(90^\circ\)?

A monochromatic beam of light traveling in Medium 1 with index of refraction \(n_1\) enters Medium 2 with index of refraction \(n_2\), where \(n_1 > n_2\). The angle of incidence relative to the normal is \(\theta_1\) and the angle of refraction is \(\theta_2\). Which of the following graphs best represents \(\sin\theta_2\) as a function of \(\sin\theta_1\) for incident angles from \(0^\circ\) up to \(90^\circ\)?

![A horizontal boundary line separates Medium 1 above from Medium 2 below, labeled n_1 and n_2 respectively with n_1 > n_2. A dashed vertical normal line passes through the boundary. An incident light ray in Medium 1 travels downward and rightward toward the boundary, making an angle theta_1 with the normal line. A refracted ray in Medium 2 continues downward and rightward away from the normal line, making an angle theta_2 with the normal line, where theta_2 > theta_1. No other labels, lines, text, or axes appear.](https://nerd-notes.com/wp-content/uploads/ubq-frq-generated/stem-fig-1-1785826342-DxwRa8.jpg)

- **A.** Graph A
- **B.** Graph B
- **C.** Graph C
- **D.** Graph D

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/117502/*