---
title: "A wheel mounted on a frictionless fixed axis is subjected to a position-dependent net torque given by \\(\\tau(\\theta) = \\tau_0 \\sin\\theta\\), where \\(\\tau_0\\) is a positive constant and \\(\\theta\\) is the angular displacement from its initial position. What is the total work done on the wheel by this torque as it rotates from \\(\\theta = 0\\) to \\(\\theta = \\dfrac{\\pi}{2}\\)?"
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url: "https://nerd-notes.com/ubq/117565/"
date_modified: "2026-08-04T07:49:08+00:00"
---

# A wheel mounted on a frictionless fixed axis is subjected to a position-dependent net torque given by \(\tau(\theta) = \tau_0 \sin\theta\), where \(\tau_0\) is a positive constant and \(\theta\) is the angular displacement from its initial position. What is the total work done on the wheel by this torque as it rotates from \(\theta = 0\) to \(\theta = \dfrac{\pi}{2}\)?

A wheel mounted on a frictionless fixed axis is subjected to a position-dependent net torque given by \(\tau(\theta) = \tau_0 \sin\theta\), where \(\tau_0\) is a positive constant and \(\theta\) is the angular displacement from its initial position. What is the total work done on the wheel by this torque as it rotates from \(\theta = 0\) to \(\theta = \dfrac{\pi}{2}\)?

- **A.** \(0\)
- **B.** \(\dfrac{1}{2}\tau_0\)
- **C.** \(\tau_0\)
- **D.** \(\dfrac{\pi}{2}\tau_0\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/117565/*