---
title: "An electron of mass \\(m_e\\) and charge magnitude \\(e\\) is released from rest in a region containing a uniform electric field of magnitude \\(E\\) directed vertically downward. Gravitational effects are negligible. Which of the following correctly pairs the direction and the magnitude of the electron’s initial acceleration?"
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url: "https://nerd-notes.com/ubq/117886/"
date_modified: "2026-08-04T08:02:23+00:00"
---

# An electron of mass \(m_e\) and charge magnitude \(e\) is released from rest in a region containing a uniform electric field of magnitude \(E\) directed vertically downward. Gravitational effects are negligible. Which of the following correctly pairs the direction and the magnitude of the electron’s initial acceleration?

An electron of mass \(m_e\) and charge magnitude \(e\) is released from rest in a region containing a uniform electric field of magnitude \(E\) directed vertically downward. Gravitational effects are negligible. Which of the following correctly pairs the direction and the magnitude of the electron's initial acceleration?

![A schematic diagram showing a uniform electric field in a vacuum. Five parallel, evenly spaced vertical arrows point downward, each labeled \(\vec{E}\). In the center of the field region, a solid black circle represents an electron, labeled \(e^-\). No forces, velocity vectors, or coordinate axes are shown.](https://nerd-notes.com/wp-content/uploads/ubq-frq-generated/stem-fig-1-1785830542-XlFKrl.jpg)

- **A.** Direction: Upward | Magnitude: \(\dfrac{eE}{m_e}\)
- **B.** Direction: Downward | Magnitude: \(\dfrac{eE}{m_e}\)
- **C.** Direction: Upward | Magnitude: \(\dfrac{m_e E}{e}\)
- **D.** Direction: Downward | Magnitude: \(\dfrac{m_e E}{e}\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/117886/*