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title: "Two uncharged capacitors with capacitances \\(C_1 = C\\) and \\(C_2 = 2C\\) are connected in parallel across an ideal battery that maintains a constant potential difference \\(V_0\\). What is the equivalent capacitance \\(C_{\\text{eq}}\\)` of the combination, and what is the ratio \\(Q_2 / Q_1\\) of the charge stored on capacitor 2 to the charge stored on capacitor 1?"
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url: "https://nerd-notes.com/ubq/118190/"
date_modified: "2026-08-04T08:07:58+00:00"
---

# Two uncharged capacitors with capacitances \(C_1 = C\) and \(C_2 = 2C\) are connected in parallel across an ideal battery that maintains a constant potential difference \(V_0\). What is the equivalent capacitance \(C_{\text{eq}}\)` of the combination, and what is the ratio \(Q_2 / Q_1\) of the charge stored on capacitor 2 to the charge stored on capacitor 1?

Two uncharged capacitors with capacitances \(C_1 = C\) and \(C_2 = 2C\) are connected in parallel across an ideal battery that maintains a constant potential difference \(V_0\). What is the equivalent capacitance \(C_{\text{eq}}\)` of the combination, and what is the ratio \(Q_2 / Q_1\) of the charge stored on capacitor 2 to the charge stored on capacitor 1?

![A schematic diagram of a parallel circuit. On the left side, a vertical battery symbol is labeled with potential difference V_0, with its long positive plate at the top. Wires extend from the top and bottom of the battery to form a rectangular loop that splits into two parallel vertical branches. The left branch contains capacitor C_1 labeled C. The right branch contains capacitor C_2 labeled 2C. No other labels, text, or elements appear.](https://nerd-notes.com/wp-content/uploads/ubq-frq-generated/stem-fig-1-1785830878-yMDwYl.jpg)

- **A.** \(C_{\text{eq}} = \dfrac{2}{3}C\), \(\dfrac{Q_2}{Q_1} = \dfrac{1}{2}\)
- **B.** \(C_{\text{eq}} = \dfrac{2}{3}C\), \(\dfrac{Q_2}{Q_1} = 2\)
- **C.** \(C_{\text{eq}} = 3C\), \(\dfrac{Q_2}{Q_1} = \dfrac{1}{2}\)
- **D.** \(C_{\text{eq}} = 3C\), \(\dfrac{Q_2}{Q_1} = 2\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/118190/*