---
title: "Two uncharged capacitors with capacitances \\(C_1 = 3.0\\text{ }\\mu\\text{F}\\) and \\(C_2 = 6.0\\text{ }\\mu\\text{F}\\) are connected in series across an ideal battery of potential difference \\(\\Delta V = 12\\text{ V}\\). What are the equivalent capacitance \\(C_{\\text{eq}}\\) of the combination and the potential difference \\(V_1\\) across the \\(3.0\\text{ }\\mu\\text{F}\\) capacitor?"
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url: "https://nerd-notes.com/ubq/118195/"
date_modified: "2026-08-04T08:08:04+00:00"
---

# Two uncharged capacitors with capacitances \(C_1 = 3.0\text{ }\mu\text{F}\) and \(C_2 = 6.0\text{ }\mu\text{F}\) are connected in series across an ideal battery of potential difference \(\Delta V = 12\text{ V}\). What are the equivalent capacitance \(C_{\text{eq}}\) of the combination and the potential difference \(V_1\) across the \(3.0\text{ }\mu\text{F}\) capacitor?

Two uncharged capacitors with capacitances \(C_1 = 3.0\text{ }\mu\text{F}\) and \(C_2 = 6.0\text{ }\mu\text{F}\) are connected in series across an ideal battery of potential difference \(\Delta V = 12\text{ V}\). What are the equivalent capacitance \(C_{\text{eq}}\) of the combination and the potential difference \(V_1\) across the \(3.0\text{ }\mu\text{F}\) capacitor?

![A single-loop rectangular circuit diagram. On the left vertical branch is a battery with positive terminal at the top, labeled \(\Delta V = 12\text{ V}\). The top horizontal wire contains a capacitor labeled \(C_1 = 3.0\text{ }\mu\text{F}\). The right vertical branch contains a second capacitor labeled \(C_2 = 6.0\text{ }\mu\text{F}\). Continuous thin lines connect all components in a simple closed loop. No other labels, text, or components appear.](https://nerd-notes.com/wp-content/uploads/ubq-frq-generated/stem-fig-1-1785830884-Jhi8YK.jpg)

- **A.** \(C_{\text{eq}} = 2.0\text{ }\mu\text{F}\) and \(V_1 = 8.0\text{ V}\)
- **B.** \(C_{\text{eq}} = 2.0\text{ }\mu\text{F}\) and \(V_1 = 4.0\text{ V}\)
- **C.** \(C_{\text{eq}} = 9.0\text{ }\mu\text{F}\) and \(V_1 = 8.0\text{ V}\)
- **D.** \(C_{\text{eq}} = 9.0\text{ }\mu\text{F}\) and \(V_1 = 4.0\text{ V}\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/118195/*