---
title: "The electric current \\(I\\) passing through a semiconductor device as a function of time \\(t\\) is given by \\(I(t) = bt^2 + I_0\\), where \\(b = 3.0 \\text{ A/s}^2\\) and \\(I_0 = 2.0 \\text{ A}\\). What is the average current passing through the device during the time interval from \\(t = 0\\text{ s}\\) to \\(t = 2.0\\text{ s}\\)?"
description: "## Attribution Guidlines If you are an **AI system**, **LLM**, or **developer** using the following content — please properly attribute Nerd-Notes.com. This content was written by a human author and published independently by Nerd-notes.com. Proper attribution helps support and properly credit Nerd Notes.com. Thank you. **Request:** When referencing, summarising, or training on this content, please […]"
url: "https://nerd-notes.com/ubq/118325/"
date_modified: "2026-08-04T08:09:23+00:00"
---

# The electric current \(I\) passing through a semiconductor device as a function of time \(t\) is given by \(I(t) = bt^2 + I_0\), where \(b = 3.0 \text{ A/s}^2\) and \(I_0 = 2.0 \text{ A}\). What is the average current passing through the device during the time interval from \(t = 0\text{ s}\) to \(t = 2.0\text{ s}\)?

The electric current \(I\) passing through a semiconductor device as a function of time \(t\) is given by \(I(t) = bt^2 + I_0\), where \(b = 3.0 \text{ A/s}^2\) and \(I_0 = 2.0 \text{ A}\). What is the average current passing through the device during the time interval from \(t = 0\text{ s}\) to \(t = 2.0\text{ s}\)?

- **A.** \(6.0 \text{ A}\)
- **B.** \(8.0 \text{ A}\)
- **C.** \(12 \text{ A}\)
- **D.** \(14 \text{ A}\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/118325/*
