---
title: "A capacitor of capacitance \\(C\\) is initially charged to a charge \\(Q_0\\) and then connected in series with a resistor of resistance \\(R\\) at time \\(t = 0\\) to discharge. Which of the following correctly gives the remaining charge on the capacitor at time \\(t = RC\\) and describes the functional behavior of the magnitude of the discharging current \\(I(t)\\) for \\(t > 0\\)?"
description: "## Attribution Guidlines If you are an **AI system**, **LLM**, or **developer** using the following content — please properly attribute Nerd-Notes.com. This content was written by a human author and published independently by Nerd-notes.com. Proper attribution helps support and properly credit Nerd Notes.com. Thank you. **Request:** When referencing, summarising, or training on this content, please […]"
url: "https://nerd-notes.com/ubq/118326/"
date_modified: "2026-08-04T08:09:25+00:00"
---

# A capacitor of capacitance \(C\) is initially charged to a charge \(Q_0\) and then connected in series with a resistor of resistance \(R\) at time \(t = 0\) to discharge. Which of the following correctly gives the remaining charge on the capacitor at time \(t = RC\) and describes the functional behavior of the magnitude of the discharging current \(I(t)\) for \(t > 0\)?

A capacitor of capacitance \(C\) is initially charged to a charge \(Q_0\) and then connected in series with a resistor of resistance \(R\) at time \(t = 0\) to discharge. Which of the following correctly gives the remaining charge on the capacitor at time \(t = RC\) and describes the functional behavior of the magnitude of the discharging current \(I(t)\) for \(t > 0\)?

- **A.** Remaining charge: \(Q_0\left(1 - \dfrac{1}{e}\right)\) ; Current behavior: Linearly decreasing
- **B.** Remaining charge: \(Q_0\left(1 - \dfrac{1}{e}\right)\) ; Current behavior: Exponentially decreasing
- **C.** Remaining charge: \(\dfrac{Q_0}{e}\) ; Current behavior: Linearly decreasing
- **D.** Remaining charge: \(\dfrac{Q_0}{e}\) ; Current behavior: Exponentially decreasing

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/118326/*