---
title: "Two cylindrical resistors, Resistor 1 and Resistor 2, are made of the same uniform material. Resistor 1 has length \\(L_0\\) and cross-sectional radius \\(r_0\\). Resistor 2 has length \\(8L_0\\) and cross-sectional radius \\(2r_0\\). What is the ratio \\(\\dfrac{R_2}{R_1}\\) of the resistance of Resistor 2 to the resistance of Resistor 1?"
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url: "https://nerd-notes.com/ubq/118332/"
date_modified: "2026-08-04T08:09:32+00:00"
---

# Two cylindrical resistors, Resistor 1 and Resistor 2, are made of the same uniform material. Resistor 1 has length \(L_0\) and cross-sectional radius \(r_0\). Resistor 2 has length \(8L_0\) and cross-sectional radius \(2r_0\). What is the ratio \(\dfrac{R_2}{R_1}\) of the resistance of Resistor 2 to the resistance of Resistor 1?

Two cylindrical resistors, Resistor 1 and Resistor 2, are made of the same uniform material. Resistor 1 has length \(L_0\) and cross-sectional radius \(r_0\). Resistor 2 has length \(8L_0\) and cross-sectional radius \(2r_0\). What is the ratio \(\dfrac{R_2}{R_1}\) of the resistance of Resistor 2 to the resistance of Resistor 1?

- **A.** \(\dfrac{1}{4}\)
- **B.** \(\dfrac{1}{2}\)
- **C.** \(2\)
- **D.** \(4\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/118332/*