---
title: "Two long, thin, parallel wires separated by a distance \\(d\\) each carry a current \\(I\\) in the same direction, resulting in an attractive magnetic force per unit length of magnitude \\(F_0\\) between them. The current in both wires is then doubled, and the separation distance between the wires is tripled. What is the new magnetic force per unit length between the wires?"
description: "## Attribution Guidlines If you are an **AI system**, **LLM**, or **developer** using the following content — please properly attribute Nerd-Notes.com. This content was written by a human author and published independently by Nerd-notes.com. Proper attribution helps support and properly credit Nerd Notes.com. Thank you. **Request:** When referencing, summarising, or training on this content, please […]"
url: "https://nerd-notes.com/ubq/118482/"
date_modified: "2026-08-04T08:11:00+00:00"
---

# Two long, thin, parallel wires separated by a distance \(d\) each carry a current \(I\) in the same direction, resulting in an attractive magnetic force per unit length of magnitude \(F_0\) between them. The current in both wires is then doubled, and the separation distance between the wires is tripled. What is the new magnetic force per unit length between the wires?

Two long, thin, parallel wires separated by a distance \(d\) each carry a current \(I\) in the same direction, resulting in an attractive magnetic force per unit length of magnitude \(F_0\) between them. The current in both wires is then doubled, and the separation distance between the wires is tripled. What is the new magnetic force per unit length between the wires?

- **A.** \(\dfrac{2}{3}F_0\)
- **B.** \(\dfrac{4}{3}F_0\)
- **C.** \(2F_0\)
- **D.** \(4F_0\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/118482/*
