---
title: "An ideal radio tuning circuit consists of an inductor with inductance \\(L\\) and a capacitor with capacitance \\(C\\), resulting in an oscillation frequency of \\(f_0\\). The circuit is adjusted by replacing the inductor with one of inductance \\(9L\\) and replacing the capacitor with one of capacitance \\(\\dfrac{1}{4}C\\). What is the new resonant frequency of the modified circuit in terms of \\(f_0\\)?"
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url: "https://nerd-notes.com/ubq/118629/"
date_modified: "2026-08-04T08:13:15+00:00"
---

# An ideal radio tuning circuit consists of an inductor with inductance \(L\) and a capacitor with capacitance \(C\), resulting in an oscillation frequency of \(f_0\). The circuit is adjusted by replacing the inductor with one of inductance \(9L\) and replacing the capacitor with one of capacitance \(\dfrac{1}{4}C\). What is the new resonant frequency of the modified circuit in terms of \(f_0\)?

An ideal radio tuning circuit consists of an inductor with inductance \(L\) and a capacitor with capacitance \(C\), resulting in an oscillation frequency of \(f_0\). The circuit is adjusted by replacing the inductor with one of inductance \(9L\) and replacing the capacitor with one of capacitance \(\dfrac{1}{4}C\). What is the new resonant frequency of the modified circuit in terms of \(f_0\)?

- **A.** \(\dfrac{2}{3}f_0\)
- **B.** \(\dfrac{3}{2}f_0\)
- **C.** \(\dfrac{4}{9}f_0\)
- **D.** \(\dfrac{9}{4}f_0\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/118629/*