---
title: "A flat circular loop of wire with area \\(A\\) rotates at a constant angular speed \\(\\omega\\) in a region of uniform magnetic field \\(\\vec{B}\\). The angle between the magnetic field vector and the normal vector to the loop’s plane is given by \\(\\theta(t) = \\omega t\\). At the instant when the magnitude of the induced electromotive force (EMF) in the loop is at its maximum, which choice correctly pairs the magnetic flux \\(\\Phi_B\\) through the loop with the angle \\(\\theta\\)?"
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url: "https://nerd-notes.com/ubq/118656/"
date_modified: "2026-08-04T08:13:32+00:00"
---

# A flat circular loop of wire with area \(A\) rotates at a constant angular speed \(\omega\) in a region of uniform magnetic field \(\vec{B}\). The angle between the magnetic field vector and the normal vector to the loop’s plane is given by \(\theta(t) = \omega t\). At the instant when the magnitude of the induced electromotive force (EMF) in the loop is at its maximum, which choice correctly pairs the magnetic flux \(\Phi_B\) through the loop with the angle \(\theta\)?

A flat circular loop of wire with area \(A\) rotates at a constant angular speed \(\omega\) in a region of uniform magnetic field \(\vec{B}\). The angle between the magnetic field vector and the normal vector to the loop's plane is given by \(\theta(t) = \omega t\). At the instant when the magnitude of the induced electromotive force (EMF) in the loop is at its maximum, which choice correctly pairs the magnetic flux \(\Phi_B\) through the loop with the angle \(\theta\)?

- **A.** Magnetic Flux: \(\Phi_B = 0\) | Angle: \(\theta = 90^\circ\)
- **B.** Magnetic Flux: \(\Phi_B = B A\) | Angle: \(\theta = 0^\circ\)
- **C.** Magnetic Flux: \(\Phi_B = 0\) | Angle: \(\theta = 0^\circ\)
- **D.** Magnetic Flux: \(\Phi_B = B A\) | Angle: \(\theta = 90^\circ\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/118656/*
