---
title: "A student monitors the decomposition of hydrogen peroxide according to the equation \\(2\\text{H}_2\\text{O}_2(aq) \\rightarrow 2\\text{H}_2\\text{O}(l) + \\text{O}_2(g)\\). The concentration of \\(\\text{H}_2\\text{O}_2(aq)\\) measured at various times during the reaction is recorded in the table below.  | Time (s) | \\([\\text{H}_2\\text{O}_2]\\) (M) | |—|—| | 0.0 | 1.00 | | 10.0 | 0.80 | | 50.0 | 0.20 | | 60.0 | 0.10 |  Based on the data in the table, what is the average rate of disappearance of \\(\\text{H}_2\\text{O}_2(aq)\\) between \\(t = 10.0\\text{ s}\\) and \\(t = 50.0\\text{ s}\\)?"
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url: "https://nerd-notes.com/ubq/119221/"
date_modified: "2026-08-19T12:39:25+00:00"
---

# A student monitors the decomposition of hydrogen peroxide according to the equation \(2\text{H}_2\text{O}_2(aq) \rightarrow 2\text{H}_2\text{O}(l) + \text{O}_2(g)\). The concentration of \(\text{H}_2\text{O}_2(aq)\) measured at various times during the reaction is recorded in the table below.

| Time (s) | \([\text{H}_2\text{O}_2]\) (M) |
|—|—|
| 0.0 | 1.00 |
| 10.0 | 0.80 |
| 50.0 | 0.20 |
| 60.0 | 0.10 |

Based on the data in the table, what is the average rate of disappearance of \(\text{H}_2\text{O}_2(aq)\) between \(t = 10.0\text{ s}\) and \(t = 50.0\text{ s}\)?

A student monitors the decomposition of hydrogen peroxide according to the equation \(2\text{H}_2\text{O}_2(aq) \rightarrow 2\text{H}_2\text{O}(l) + \text{O}_2(g)\). The concentration of \(\text{H}_2\text{O}_2(aq)\) measured at various times during the reaction is recorded in the table below.

| Time (s) | \([\text{H}_2\text{O}_2]\) (M) |
|---|---|
| 0.0 | 1.00 |
| 10.0 | 0.80 |
| 50.0 | 0.20 |
| 60.0 | 0.10 |

Based on the data in the table, what is the average rate of disappearance of \(\text{H}_2\text{O}_2(aq)\) between \(t = 10.0\text{ s}\) and \(t = 50.0\text{ s}\)?

- **A.** \(0.0033\text{ M}\cdot\text{s}^{-1}\)
- **B.** \(0.0050\text{ M}\cdot\text{s}^{-1}\)
- **C.** \(0.015\text{ M}\cdot\text{s}^{-1}\)
- **D.** \(0.020\text{ M}\cdot\text{s}^{-1}\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/119221/*