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title: "A student performs two calorimetry trials in an insulated vessel containing water. In Trial 1, a process transfers heat \\(q\\) to \\(50.0\\text{ g}\\) of water, resulting in a temperature change of \\(\\Delta T_1\\). In Trial 2, the same process transfers the same amount of heat \\(q\\) to \\(100.0\\text{ g}\\) of water, resulting in a temperature change of \\(\\Delta T_2\\). Assuming no heat is lost to the surroundings, what is the ratio \\(\\dfrac{\\Delta T_1}{\\Delta T_2}\\)?"
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url: "https://nerd-notes.com/ubq/119260/"
date_modified: "2026-08-19T12:39:34+00:00"
---

# A student performs two calorimetry trials in an insulated vessel containing water. In Trial 1, a process transfers heat \(q\) to \(50.0\text{ g}\) of water, resulting in a temperature change of \(\Delta T_1\). In Trial 2, the same process transfers the same amount of heat \(q\) to \(100.0\text{ g}\) of water, resulting in a temperature change of \(\Delta T_2\). Assuming no heat is lost to the surroundings, what is the ratio \(\dfrac{\Delta T_1}{\Delta T_2}\)?

A student performs two calorimetry trials in an insulated vessel containing water. In Trial 1, a process transfers heat \(q\) to \(50.0\text{ g}\) of water, resulting in a temperature change of \(\Delta T_1\). In Trial 2, the same process transfers the same amount of heat \(q\) to \(100.0\text{ g}\) of water, resulting in a temperature change of \(\Delta T_2\). Assuming no heat is lost to the surroundings, what is the ratio \(\dfrac{\Delta T_1}{\Delta T_2}\)?

- **A.** \(\dfrac{1}{4}\)
- **B.** \(\dfrac{1}{2}\)
- **C.** \(2\)
- **D.** \(4\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/119260/*