---
title: "A student prepares a saturated solution of calcium fluoride, \\(\\text{CaF}_2(s)\\), at \\(25^\\circ\\text{C}\\) and determines that the molar solubility of \\(\\text{CaF}_2\\) is \\(2.0 \\times 10^{-4} \\text{ M}\\). Based on this measurement, what is the value of the solubility product constant, \\(K_{sp}\\), for \\(\\text{CaF}_2\\) at \\(25^\\circ\\text{C}\\)?"
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url: "https://nerd-notes.com/ubq/119320/"
date_modified: "2026-08-19T12:39:48+00:00"
---

# A student prepares a saturated solution of calcium fluoride, \(\text{CaF}_2(s)\), at \(25^\circ\text{C}\) and determines that the molar solubility of \(\text{CaF}_2\) is \(2.0 \times 10^{-4} \text{ M}\). Based on this measurement, what is the value of the solubility product constant, \(K_{sp}\), for \(\text{CaF}_2\) at \(25^\circ\text{C}\)?

A student prepares a saturated solution of calcium fluoride, \(\text{CaF}_2(s)\), at \(25^\circ\text{C}\) and determines that the molar solubility of \(\text{CaF}_2\) is \(2.0 \times 10^{-4} \text{ M}\). Based on this measurement, what is the value of the solubility product constant, \(K_{sp}\), for \(\text{CaF}_2\) at \(25^\circ\text{C}\)?

- **A.** \(3.2 \times 10^{-11}\)
- **B.** \(6.4 \times 10^{-11}\)
- **C.** \(8.0 \times 10^{-8}\)
- **D.** \(1.6 \times 10^{-7}\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/119320/*