---
title: "A hospital uses the radioactive isotope \\(^{18}\\text{F}\\) as a medical imaging tracer. The isotope undergoes first-order decay with a rate constant of \\(6.30 \\times 10^{-3}\\ \\text{min}^{-1}\\).  What is the half-life of \\(^{18}\\text{F}\\)?"
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url: "https://nerd-notes.com/ubq/119333/"
date_modified: "2026-08-19T12:39:51+00:00"
---

# A hospital uses the radioactive isotope \(^{18}\text{F}\) as a medical imaging tracer. The isotope undergoes first-order decay with a rate constant of \(6.30 \times 10^{-3}\ \text{min}^{-1}\).

What is the half-life of \(^{18}\text{F}\)?

A hospital uses the radioactive isotope \(^{18}\text{F}\) as a medical imaging tracer. The isotope undergoes first-order decay with a rate constant of \(6.30 \times 10^{-3}\ \text{min}^{-1}\).

What is the half-life of \(^{18}\text{F}\)?

- **A.** \(9.09 \times 10^{-3}\ \text{min}\)
- **B.** \(110\ \text{min}\)
- **C.** \(159\ \text{min}\)
- **D.** \(1100\ \text{min}\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/119333/*
