---
title: "A student titrates a sample of a monoprotic acid, \\(\\text{HA(aq)}\\), with standardized \\(\\text{NaOH(aq)}\\). The reaction is represented by  \\(\\text{HA(aq)}+\\text{OH}^-\\text{(aq)} \\rightarrow \\text{A}^-\\text{(aq)}+\\text{H}_2\\text{O(l)}\\)  | Quantity | Value | |—|—:| | Volume of acid sample | \\(25.00\\text{ mL}\\) | | Concentration of \\(\\text{NaOH(aq)}\\) | \\(0.1000\\text{ M}\\) | | Initial buret reading | \\(0.30\\text{ mL}\\) | | Final buret reading | \\(25.30\\text{ mL}\\) |  Before the initial reading is recorded, an air bubble is trapped in the buret tip. During the titration, the bubble is expelled and the tip fills completely with the titrant. The student uses the difference between the final and initial buret readings to calculate the molarity of the acid. Which of the following correctly describes how the air bubble affects the calculated molarity of \\(\\text{HA(aq)}\\)?"
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url: "https://nerd-notes.com/ubq/119372/"
date_modified: "2026-08-19T12:40:03+00:00"
---

# A student titrates a sample of a monoprotic acid, \(\text{HA(aq)}\), with standardized \(\text{NaOH(aq)}\). The reaction is represented by

\(\text{HA(aq)}+\text{OH}^-\text{(aq)} \rightarrow \text{A}^-\text{(aq)}+\text{H}_2\text{O(l)}\)

| Quantity | Value |
|—|—:|
| Volume of acid sample | \(25.00\text{ mL}\) |
| Concentration of \(\text{NaOH(aq)}\) | \(0.1000\text{ M}\) |
| Initial buret reading | \(0.30\text{ mL}\) |
| Final buret reading | \(25.30\text{ mL}\) |

Before the initial reading is recorded, an air bubble is trapped in the buret tip. During the titration, the bubble is expelled and the tip fills completely with the titrant. The student uses the difference between the final and initial buret readings to calculate the molarity of the acid. Which of the following correctly describes how the air bubble affects the calculated molarity of \(\text{HA(aq)}\)?

A student titrates a sample of a monoprotic acid, \(\text{HA(aq)}\), with standardized \(\text{NaOH(aq)}\). The reaction is represented by

\(\text{HA(aq)}+\text{OH}^-\text{(aq)} \rightarrow \text{A}^-\text{(aq)}+\text{H}_2\text{O(l)}\)

| Quantity | Value |
|---|---:|
| Volume of acid sample | \(25.00\text{ mL}\) |
| Concentration of \(\text{NaOH(aq)}\) | \(0.1000\text{ M}\) |
| Initial buret reading | \(0.30\text{ mL}\) |
| Final buret reading | \(25.30\text{ mL}\) |

Before the initial reading is recorded, an air bubble is trapped in the buret tip. During the titration, the bubble is expelled and the tip fills completely with the titrant. The student uses the difference between the final and initial buret readings to calculate the molarity of the acid. Which of the following correctly describes how the air bubble affects the calculated molarity of \(\text{HA(aq)}\)?

- **A.** The calculated molarity is too high because expelling the air bubble increases the concentration of the \(\text{NaOH(aq)}\) that subsequently enters the flask.
- **B.** The calculated molarity is too high because the recorded volume includes titrant that fills the buret tip but does not enter the flask.
- **C.** The calculated molarity is too low because some of the recorded titrant volume fills the buret tip, causing the student to use too few moles of \(\text{NaOH}\) in the calculation.
- **D.** The calculated molarity is unchanged because subtracting the initial buret reading from the final buret reading eliminates the effect of the air bubble.

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/119372/*