---
title: "A student constructs a standard galvanic cell operating at \\(298\\text{ K}\\) based on the half-reactions represented below.  \\(\\text{Zn}^{2+}\\text{(aq)} + 2e^- \\rightarrow \\text{Zn(s)} \\quad E^\\circ = -0.76\\text{ V}\\) \\(\\text{Cu}^{2+}\\text{(aq)} + 2e^- \\rightarrow \\text{Cu(s)} \\quad E^\\circ = +0.34\\text{ V}\\)  The overall reaction occurring in the cell is \\(\\text{Zn(s)} + \\text{Cu}^{2+}\\text{(aq)} \\rightarrow \\text{Zn}^{2+}\\text{(aq)} + \\text{Cu(s)}\\). What is the value of the standard Gibbs free energy change, \\(\\Delta G^\\circ\\), for the reaction at \\(298\\text{ K}\\)?"
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url: "https://nerd-notes.com/ubq/119399/"
date_modified: "2026-08-19T12:40:07+00:00"
---

# A student constructs a standard galvanic cell operating at \(298\text{ K}\) based on the half-reactions represented below.

\(\text{Zn}^{2+}\text{(aq)} + 2e^- \rightarrow \text{Zn(s)} \quad E^\circ = -0.76\text{ V}\)
\(\text{Cu}^{2+}\text{(aq)} + 2e^- \rightarrow \text{Cu(s)} \quad E^\circ = +0.34\text{ V}\)

The overall reaction occurring in the cell is \(\text{Zn(s)} + \text{Cu}^{2+}\text{(aq)} \rightarrow \text{Zn}^{2+}\text{(aq)} + \text{Cu(s)}\). What is the value of the standard Gibbs free energy change, \(\Delta G^\circ\), for the reaction at \(298\text{ K}\)?

A student constructs a standard galvanic cell operating at \(298\text{ K}\) based on the half-reactions represented below.

\(\text{Zn}^{2+}\text{(aq)} + 2e^- \rightarrow \text{Zn(s)} \quad E^\circ = -0.76\text{ V}\)
\(\text{Cu}^{2+}\text{(aq)} + 2e^- \rightarrow \text{Cu(s)} \quad E^\circ = +0.34\text{ V}\)

The overall reaction occurring in the cell is \(\text{Zn(s)} + \text{Cu}^{2+}\text{(aq)} \rightarrow \text{Zn}^{2+}\text{(aq)} + \text{Cu(s)}\). What is the value of the standard Gibbs free energy change, \(\Delta G^\circ\), for the reaction at \(298\text{ K}\)?

- **A.** \(-425\text{ kJ/mol}_{rxn}\)
- **B.** \(-318\text{ kJ/mol}_{rxn}\)
- **C.** \(-212\text{ kJ/mol}_{rxn}\)
- **D.** \(+212\text{ kJ/mol}_{rxn}\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/119399/*