---
title: "A student models the recovery of lead(II) iodide from a pigment-waste stream using the dissolution equilibrium  \\(\\text{PbI}_2\\text{(s)} \\rightleftharpoons \\text{Pb}^{2+}\\text{(aq)} + 2\\text{I}^-\\text{(aq)}\\)  At the temperature of the experiment, \\(K_{sp}=4.0\\times10^{-9}\\). Excess \\(\\text{PbI}_2\\text{(s)}\\) is added to a \\(0.020\\text{ M}\\) solution of \\(\\text{NaI(aq)}\\), which dissociates completely. Assume that the iodide ions produced by dissolution of \\(\\text{PbI}_2\\text{(s)}\\) make a negligible contribution to the total iodide concentration. What is the approximate molar solubility of \\(\\text{PbI}_2\\text{(s)}\\) in the solution?"
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date_modified: "2026-08-19T12:40:29+00:00"
---

# A student models the recovery of lead(II) iodide from a pigment-waste stream using the dissolution equilibrium

\(\text{PbI}_2\text{(s)} \rightleftharpoons \text{Pb}^{2+}\text{(aq)} + 2\text{I}^-\text{(aq)}\)

At the temperature of the experiment, \(K_{sp}=4.0\times10^{-9}\). Excess \(\text{PbI}_2\text{(s)}\) is added to a \(0.020\text{ M}\) solution of \(\text{NaI(aq)}\), which dissociates completely. Assume that the iodide ions produced by dissolution of \(\text{PbI}_2\text{(s)}\) make a negligible contribution to the total iodide concentration. What is the approximate molar solubility of \(\text{PbI}_2\text{(s)}\) in the solution?

A student models the recovery of lead(II) iodide from a pigment-waste stream using the dissolution equilibrium

\(\text{PbI}_2\text{(s)} \rightleftharpoons \text{Pb}^{2+}\text{(aq)} + 2\text{I}^-\text{(aq)}\)

At the temperature of the experiment, \(K_{sp}=4.0\times10^{-9}\). Excess \(\text{PbI}_2\text{(s)}\) is added to a \(0.020\text{ M}\) solution of \(\text{NaI(aq)}\), which dissociates completely. Assume that the iodide ions produced by dissolution of \(\text{PbI}_2\text{(s)}\) make a negligible contribution to the total iodide concentration. What is the approximate molar solubility of \(\text{PbI}_2\text{(s)}\) in the solution?

- **A.** \(5.0\times10^{-6}\text{ M}\)
- **B.** \(1.0\times10^{-5}\text{ M}\)
- **C.** \(4.5\times10^{-4}\text{ M}\)
- **D.** \(1.0\times10^{-3}\text{ M}\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/119452/*