---
title: "A student models ammonia production in a closed, rigid reactor using the equilibrium  \\[\\text{N}_2\\text{(g)}+3\\text{H}_2\\text{(g)}\\rightleftharpoons 2\\text{NH}_3\\text{(g)} \\qquad \\Delta H^\\circ=-92\\text{ kJ/mol}_{\\text{rxn}}\\]  The system is initially at equilibrium at temperature \\(T_1\\). The temperature is rapidly increased to \\(T_2\\), where \\(T_2>T_1\\), while the volume remains constant. Which statement correctly predicts the net reaction as the system reestablishes equilibrium and correctly compares \\(Q_c\\) with the new value of \\(K_c\\)?"
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url: "https://nerd-notes.com/ubq/119457/"
date_modified: "2026-08-19T12:40:30+00:00"
---

# A student models ammonia production in a closed, rigid reactor using the equilibrium

\[\text{N}_2\text{(g)}+3\text{H}_2\text{(g)}\rightleftharpoons 2\text{NH}_3\text{(g)} \qquad \Delta H^\circ=-92\text{ kJ/mol}_{\text{rxn}}\]

The system is initially at equilibrium at temperature \(T_1\). The temperature is rapidly increased to \(T_2\), where \(T_2>T_1\), while the volume remains constant. Which statement correctly predicts the net reaction as the system reestablishes equilibrium and correctly compares \(Q_c\) with the new value of \(K_c\)?

A student models ammonia production in a closed, rigid reactor using the equilibrium

\[\text{N}_2\text{(g)}+3\text{H}_2\text{(g)}\rightleftharpoons 2\text{NH}_3\text{(g)} \qquad \Delta H^\circ=-92\text{ kJ/mol}_{\text{rxn}}\]

The system is initially at equilibrium at temperature \(T_1\). The temperature is rapidly increased to \(T_2\), where \(T_2>T_1\), while the volume remains constant. Which statement correctly predicts the net reaction as the system reestablishes equilibrium and correctly compares \(Q_c\) with the new value of \(K_c\)?

- **A.** The net reaction proceeds toward \(\text{NH}_3\text{(g)}\) because increasing the temperature increases \(K_c\) while \(Q_c\) is initially unchanged, making \(Q_c<K_c\).
- **B.** No net reaction occurs because increasing the temperature decreases both \(K_c\) and \(Q_c\) by the same factor, so they remain equal.
- **C.** The net reaction proceeds toward \(\text{N}_2\text{(g)}\) and \(\text{H}_2\text{(g)}\) because \(Q_c\) immediately increases while \(K_c\) remains unchanged, making \(Q_c>K_c\).
- **D.** The net reaction proceeds toward \(\text{N}_2\text{(g)}\) and \(\text{H}_2\text{(g)}\) because \(K_c\) decreases while \(Q_c\) is initially unchanged, making \(Q_c>K_c\).

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/119457/*
