---
title: "A student heats a \\(5.00 \\text{ g}\\) sample of hydrated copper(II) sulfate in a crucible according to the equation below.  \\[ \\text{CuSO}_4\\cdot 5\\text{H}_2\\text{O}(s) \\rightarrow \\text{CuSO}_4(s) + 5\\text{ H}_2\\text{O}(g) \\]  The molar mass of \\(\\text{CuSO}_4\\cdot 5\\text{H}_2\\text{O}\\) is \\(250 \\text{ g/mol}\\), the molar mass of anhydrous \\(\\text{CuSO}_4\\) is \\(160 \\text{ g/mol}\\), and the molar mass of \\(\\text{H}_2\\text{O}\\) is \\(18.0 \\text{ g/mol}\\). Assuming all water of hydration is completely driven off, what mass of \\(\\text{H}_2\\text{O}(g)\\) is released during the experiment?"
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url: "https://nerd-notes.com/ubq/119571/"
date_modified: "2026-08-21T06:53:53+00:00"
---

# A student heats a \(5.00 \text{ g}\) sample of hydrated copper(II) sulfate in a crucible according to the equation below.

\[ \text{CuSO}_4\cdot 5\text{H}_2\text{O}(s) \rightarrow \text{CuSO}_4(s) + 5\text{ H}_2\text{O}(g) \]

The molar mass of \(\text{CuSO}_4\cdot 5\text{H}_2\text{O}\) is \(250 \text{ g/mol}\), the molar mass of anhydrous \(\text{CuSO}_4\) is \(160 \text{ g/mol}\), and the molar mass of \(\text{H}_2\text{O}\) is \(18.0 \text{ g/mol}\). Assuming all water of hydration is completely driven off, what mass of \(\text{H}_2\text{O}(g)\) is released during the experiment?

A student heats a \(5.00 \text{ g}\) sample of hydrated copper(II) sulfate in a crucible according to the equation below.

\[ \text{CuSO}_4\cdot 5\text{H}_2\text{O}(s) \rightarrow \text{CuSO}_4(s) + 5\text{ H}_2\text{O}(g) \]

The molar mass of \(\text{CuSO}_4\cdot 5\text{H}_2\text{O}\) is \(250 \text{ g/mol}\), the molar mass of anhydrous \(\text{CuSO}_4\) is \(160 \text{ g/mol}\), and the molar mass of \(\text{H}_2\text{O}\) is \(18.0 \text{ g/mol}\). Assuming all water of hydration is completely driven off, what mass of \(\text{H}_2\text{O}(g)\) is released during the experiment?

- **A.** \(1.80 \text{ g}\)
- **B.** \(2.50 \text{ g}\)
- **C.** \(3.20 \text{ g}\)
- **D.** \(3.60 \text{ g}\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/119571/*