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title: "A student mixes \\(100.0\\text{ mL}\\) of \\(0.10\\text{ M Pb(NO}_3)_2\\text{(aq)}\\) with \\(100.0\\text{ mL}\\) of \\(0.10\\text{ M KI(aq)}\\) at \\(25^\\circ\\text{C}\\). A precipitate of \\(\\text{PbI}_2\\text{(s)}\\) forms according to the balanced equation below.  \\[ \\text{Pb(NO}_3)_2\\text{(aq)} + 2\\,\\text{KI(aq)} \\rightarrow \\text{PbI}_2\\text{(s)} + 2\\,\\text{KNO}_3\\text{(aq)} \\]  The molar mass of \\(\\text{PbI}_2\\) is \\(461\\text{ g/mol}\\). Assuming the reaction goes to completion, what is the maximum mass of \\(\\text{PbI}_2\\text{(s)}\\) that can be produced?"
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url: "https://nerd-notes.com/ubq/119654/"
date_modified: "2026-08-21T08:11:57+00:00"
---

# A student mixes \(100.0\text{ mL}\) of \(0.10\text{ M Pb(NO}_3)_2\text{(aq)}\) with \(100.0\text{ mL}\) of \(0.10\text{ M KI(aq)}\) at \(25^\circ\text{C}\). A precipitate of \(\text{PbI}_2\text{(s)}\) forms according to the balanced equation below.

\[ \text{Pb(NO}_3)_2\text{(aq)} + 2\,\text{KI(aq)} \rightarrow \text{PbI}_2\text{(s)} + 2\,\text{KNO}_3\text{(aq)} \]

The molar mass of \(\text{PbI}_2\) is \(461\text{ g/mol}\). Assuming the reaction goes to completion, what is the maximum mass of \(\text{PbI}_2\text{(s)}\) that can be produced?

A student mixes \(100.0\text{ mL}\) of \(0.10\text{ M Pb(NO}_3)_2\text{(aq)}\) with \(100.0\text{ mL}\) of \(0.10\text{ M KI(aq)}\) at \(25^\circ\text{C}\). A precipitate of \(\text{PbI}_2\text{(s)}\) forms according to the balanced equation below.

\[ \text{Pb(NO}_3)_2\text{(aq)} + 2\,\text{KI(aq)} \rightarrow \text{PbI}_2\text{(s)} + 2\,\text{KNO}_3\text{(aq)} \]

The molar mass of \(\text{PbI}_2\) is \(461\text{ g/mol}\). Assuming the reaction goes to completion, what is the maximum mass of \(\text{PbI}_2\text{(s)}\) that can be produced?

- **A.** \(2.3\text{ g}\)
- **B.** \(4.6\text{ g}\)
- **C.** \(6.9\text{ g}\)
- **D.** \(9.2\text{ g}\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/119654/*