---
title: "A student investigates the first-order gas-phase decomposition of sulfuryl chloride, \\(\\text{SO}_2\\text{Cl}_2\\text{(g)}\\), according to the balanced equation below:  \\[\\text{SO}_2\\text{Cl}_2\\text{(g)} \\rightarrow \\text{SO}_2\\text{(g)} + \\text{Cl}_2\\text{(g)}\\]  At a certain temperature, the half-life of the reaction is \\(15\\text{ min}\\). If a sample of pure \\(\\text{SO}_2\\text{Cl}_2\\text{(g)}\\) is introduced into a rigid container at an initial concentration of \\(0.80\\text{ M}\\), what is the concentration of \\(\\text{SO}_2\\text{Cl}_2\\text{(g)}\\) remaining after \\(60\\text{ min}\\) of reaction?"
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url: "https://nerd-notes.com/ubq/119664/"
date_modified: "2026-08-21T08:11:59+00:00"
---

# A student investigates the first-order gas-phase decomposition of sulfuryl chloride, \(\text{SO}_2\text{Cl}_2\text{(g)}\), according to the balanced equation below:

\[\text{SO}_2\text{Cl}_2\text{(g)} \rightarrow \text{SO}_2\text{(g)} + \text{Cl}_2\text{(g)}\]

At a certain temperature, the half-life of the reaction is \(15\text{ min}\). If a sample of pure \(\text{SO}_2\text{Cl}_2\text{(g)}\) is introduced into a rigid container at an initial concentration of \(0.80\text{ M}\), what is the concentration of \(\text{SO}_2\text{Cl}_2\text{(g)}\) remaining after \(60\text{ min}\) of reaction?

A student investigates the first-order gas-phase decomposition of sulfuryl chloride, \(\text{SO}_2\text{Cl}_2\text{(g)}\), according to the balanced equation below:

\[\text{SO}_2\text{Cl}_2\text{(g)} \rightarrow \text{SO}_2\text{(g)} + \text{Cl}_2\text{(g)}\]

At a certain temperature, the half-life of the reaction is \(15\text{ min}\). If a sample of pure \(\text{SO}_2\text{Cl}_2\text{(g)}\) is introduced into a rigid container at an initial concentration of \(0.80\text{ M}\), what is the concentration of \(\text{SO}_2\text{Cl}_2\text{(g)}\) remaining after \(60\text{ min}\) of reaction?

- **A.** \(0.013\text{ M}\)
- **B.** \(0.025\text{ M}\)
- **C.** \(0.050\text{ M}\)
- **D.** \(0.10\text{ M}\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/119664/*