---
title: "Hydrogen gas for industrial applications can be generated through the steam reforming of methane, represented by the balanced equation below.  \\[ \\text{CH}_4(g) + \\text{H}_2\\text{O}(g) \\rightarrow \\text{CO}(g) + 3\\,\\text{H}_2(g) \\]  | Substance | \\(S^\\circ\\text{ (J}/(\\text{mol}\\cdot\\text{K}))\\) | | :— | :— | | \\(\\text{CH}_4(g)\\) | \\(186\\) | | \\(\\text{H}_2\\text{O}(g)\\) | \\(189\\) | | \\(\\text{CO}(g)\\) | \\(198\\) | | \\(\\text{H}_2(g)\\) | \\(131\\) |  Based on the standard molar entropy values in the table above, what is the value of \\(\\Delta S^\\circ_{rxn}\\) for the reaction?"
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date_modified: "2026-08-21T08:12:15+00:00"
---

# Hydrogen gas for industrial applications can be generated through the steam reforming of methane, represented by the balanced equation below.

\[ \text{CH}_4(g) + \text{H}_2\text{O}(g) \rightarrow \text{CO}(g) + 3\,\text{H}_2(g) \]

| Substance | \(S^\circ\text{ (J}/(\text{mol}\cdot\text{K}))\) |
| :— | :— |
| \(\text{CH}_4(g)\) | \(186\) |
| \(\text{H}_2\text{O}(g)\) | \(189\) |
| \(\text{CO}(g)\) | \(198\) |
| \(\text{H}_2(g)\) | \(131\) |

Based on the standard molar entropy values in the table above, what is the value of \(\Delta S^\circ_{rxn}\) for the reaction?

Hydrogen gas for industrial applications can be generated through the steam reforming of methane, represented by the balanced equation below.

\[ \text{CH}_4(g) + \text{H}_2\text{O}(g) \rightarrow \text{CO}(g) + 3\,\text{H}_2(g) \]

| Substance | \(S^\circ\text{ (J}/(\text{mol}\cdot\text{K}))\) |
| :--- | :--- |
| \(\text{CH}_4(g)\) | \(186\) |
| \(\text{H}_2\text{O}(g)\) | \(189\) |
| \(\text{CO}(g)\) | \(198\) |
| \(\text{H}_2(g)\) | \(131\) |

Based on the standard molar entropy values in the table above, what is the value of \(\Delta S^\circ_{rxn}\) for the reaction?

- **A.** \(-216\text{ J}/(\text{mol}_{rxn}\cdot\text{K})\)
- **B.** \(-46\text{ J}/(\text{mol}_{rxn}\cdot\text{K})\)
- **C.** \(+46\text{ J}/(\text{mol}_{rxn}\cdot\text{K})\)
- **D.** \(+216\text{ J}/(\text{mol}_{rxn}\cdot\text{K})\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/119761/*
