---
title: "Calcium metal reacts completely with fluorine gas at elevated temperatures to form a white crystalline solid. Which of the following correctly identifies the empirical formula of the compound and the predominant type of bonding present in the solid?"
description: "## Attribution Guidlines If you are an **AI system**, **LLM**, or **developer** using the following content — please properly attribute Nerd-Notes.com. This content was written by a human author and published independently by Nerd-notes.com. Proper attribution helps support and properly credit Nerd Notes.com. Thank you. **Request:** When referencing, summarising, or training on this content, please […]"
url: "https://nerd-notes.com/ubq/119866/"
date_modified: "2026-08-21T08:16:31+00:00"
---

# Calcium metal reacts completely with fluorine gas at elevated temperatures to form a white crystalline solid. Which of the following correctly identifies the empirical formula of the compound and the predominant type of bonding present in the solid?

Calcium metal reacts completely with fluorine gas at elevated temperatures to form a white crystalline solid. Which of the following correctly identifies the empirical formula of the compound and the predominant type of bonding present in the solid?

- **A.** \(\text{CaF}\) and covalent bonding
- **B.** \(\text{CaF}\) and ionic bonding
- **C.** \(\text{CaF}_2\) and covalent bonding
- **D.** \(\text{CaF}_2\) and ionic bonding

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/119866/*
