---
title: "A student constructs a galvanic cell at \\(298\\text{ K}\\) based on the following overall reaction:  \\[ \\text{Cu(s)} + 2\\,\\text{Ag}^+\\text{(aq)} \\rightarrow \\text{Cu}^{2+}\\text{(aq)} + 2\\,\\text{Ag(s)} \\]  The standard reduction potentials for the relevant half-reactions are given in the table below.  | Half-Reaction | \\(E^\\circ\\text{ (V)}\\) | |—|—| | \\(\\text{Ag}^+\\text{(aq)} + \\text{e}^- \\rightarrow \\text{Ag(s)}\\) | \\(+0.80\\) | | \\(\\text{Cu}^{2+}\\text{(aq)} + 2\\,\\text{e}^- \\rightarrow \\text{Cu(s)}\\) | \\(+0.34\\) |  What is the standard cell potential, \\(E^\\circ_{\\text{cell}}\\), for the reaction?"
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date_modified: "2026-08-21T08:17:22+00:00"
---

# A student constructs a galvanic cell at \(298\text{ K}\) based on the following overall reaction:

\[ \text{Cu(s)} + 2\,\text{Ag}^+\text{(aq)} \rightarrow \text{Cu}^{2+}\text{(aq)} + 2\,\text{Ag(s)} \]

The standard reduction potentials for the relevant half-reactions are given in the table below.

| Half-Reaction | \(E^\circ\text{ (V)}\) |
|—|—|
| \(\text{Ag}^+\text{(aq)} + \text{e}^- \rightarrow \text{Ag(s)}\) | \(+0.80\) |
| \(\text{Cu}^{2+}\text{(aq)} + 2\,\text{e}^- \rightarrow \text{Cu(s)}\) | \(+0.34\) |

What is the standard cell potential, \(E^\circ_{\text{cell}}\), for the reaction?

A student constructs a galvanic cell at \(298\text{ K}\) based on the following overall reaction:

\[ \text{Cu(s)} + 2\,\text{Ag}^+\text{(aq)} \rightarrow \text{Cu}^{2+}\text{(aq)} + 2\,\text{Ag(s)} \]

The standard reduction potentials for the relevant half-reactions are given in the table below.

| Half-Reaction | \(E^\circ\text{ (V)}\) |
|---|---|
| \(\text{Ag}^+\text{(aq)} + \text{e}^- \rightarrow \text{Ag(s)}\) | \(+0.80\) |
| \(\text{Cu}^{2+}\text{(aq)} + 2\,\text{e}^- \rightarrow \text{Cu(s)}\) | \(+0.34\) |

What is the standard cell potential, \(E^\circ_{\text{cell}}\), for the reaction?

- **A.** \(+0.46\text{ V}\)
- **B.** \(+0.92\text{ V}\)
- **C.** \(+1.14\text{ V}\)
- **D.** \(+1.26\text{ V}\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/119912/*