---
title: "A student analyzes a pure sample of an unknown volatile liquid composed only of \\(\\text{C}\\), \\(\\text{H}\\), and \\(\\text{O}\\). Elemental analysis of a \\(4.40 \\text{ g}\\) sample of the liquid indicates that it contains \\(2.40 \\text{ g}\\) of carbon and \\(0.40 \\text{ g}\\) of hydrogen, with the remainder being oxygen.  In a separate trial, the student completely vaporizes a portion of the liquid and determines that a \\(0.0500 \\text{ mol}\\) sample of the vapor has a mass of \\(4.40 \\text{ g}\\).  Based on these data, what is the mass of carbon present in a \\(0.500 \\text{ mol}\\) sample of the pure compound?"
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url: "https://nerd-notes.com/ubq/120182/"
date_modified: "2026-08-21T16:02:51+00:00"
---

# A student analyzes a pure sample of an unknown volatile liquid composed only of \(\text{C}\), \(\text{H}\), and \(\text{O}\). Elemental analysis of a \(4.40 \text{ g}\) sample of the liquid indicates that it contains \(2.40 \text{ g}\) of carbon and \(0.40 \text{ g}\) of hydrogen, with the remainder being oxygen.

In a separate trial, the student completely vaporizes a portion of the liquid and determines that a \(0.0500 \text{ mol}\) sample of the vapor has a mass of \(4.40 \text{ g}\).

Based on these data, what is the mass of carbon present in a \(0.500 \text{ mol}\) sample of the pure compound?

A student analyzes a pure sample of an unknown volatile liquid composed only of \(\text{C}\), \(\text{H}\), and \(\text{O}\). Elemental analysis of a \(4.40 \text{ g}\) sample of the liquid indicates that it contains \(2.40 \text{ g}\) of carbon and \(0.40 \text{ g}\) of hydrogen, with the remainder being oxygen.

In a separate trial, the student completely vaporizes a portion of the liquid and determines that a \(0.0500 \text{ mol}\) sample of the vapor has a mass of \(4.40 \text{ g}\).

Based on these data, what is the mass of carbon present in a \(0.500 \text{ mol}\) sample of the pure compound?

- **A.** \(6.00 \text{ g}\)
- **B.** \(12.0 \text{ g}\)
- **C.** \(16.0 \text{ g}\)
- **D.** \(24.0 \text{ g}\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/120182/*