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title: "At \\(700\\text{ K}\\), the equilibrium constant \\(K_p\\) for the reaction represented below is \\(64\\).  \\[\\text{H}_2\\text{(g)} + \\text{I}_2\\text{(g)} \\rightleftharpoons 2\\,\\text{HI(g)}\\]  A rigid reaction vessel is initially charged with \\(\\text{H}_2\\text{(g)}\\) and \\(\\text{I}_2\\text{(g)}\\), each at a partial pressure of \\(1.0\\text{ atm}\\), with no \\(\\text{HI(g)}\\) present. The mixture is allowed to reach equilibrium at \\(700\\text{ K}\\). What is the equilibrium partial pressure of \\(\\text{H}_2\\text{(g)}\\)?"
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url: "https://nerd-notes.com/ubq/120286/"
date_modified: "2026-08-23T04:04:16+00:00"
---

# At \(700\text{ K}\), the equilibrium constant \(K_p\) for the reaction represented below is \(64\).

\[\text{H}_2\text{(g)} + \text{I}_2\text{(g)} \rightleftharpoons 2\,\text{HI(g)}\]

A rigid reaction vessel is initially charged with \(\text{H}_2\text{(g)}\) and \(\text{I}_2\text{(g)}\), each at a partial pressure of \(1.0\text{ atm}\), with no \(\text{HI(g)}\) present. The mixture is allowed to reach equilibrium at \(700\text{ K}\). What is the equilibrium partial pressure of \(\text{H}_2\text{(g)}\)?

At \(700\text{ K}\), the equilibrium constant \(K_p\) for the reaction represented below is \(64\).

\[\text{H}_2\text{(g)} + \text{I}_2\text{(g)} \rightleftharpoons 2\,\text{HI(g)}\]

A rigid reaction vessel is initially charged with \(\text{H}_2\text{(g)}\) and \(\text{I}_2\text{(g)}\), each at a partial pressure of \(1.0\text{ atm}\), with no \(\text{HI(g)}\) present. The mixture is allowed to reach equilibrium at \(700\text{ K}\). What is the equilibrium partial pressure of \(\text{H}_2\text{(g)}\)?

- **A.** \(0.20\text{ atm}\)
- **B.** \(0.60\text{ atm}\)
- **C.** \(0.80\text{ atm}\)
- **D.** \(1.6\text{ atm}\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/120286/*