---
title: "A 2.0 kg cart moves along a straight, horizontal, frictionless track with an initial velocity of +2.0 m/s. Starting at time t = 0 s, a net horizontal force F is applied to the cart in the direction of its motion, as represented in the force versus time graph. What is the velocity of the cart at t = 4.0 s?"
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url: "https://nerd-notes.com/ubq/120704/"
date_modified: "2026-08-23T04:42:47+00:00"
---

# A 2.0 kg cart moves along a straight, horizontal, frictionless track with an initial velocity of +2.0 m/s. Starting at time t = 0 s, a net horizontal force F is applied to the cart in the direction of its motion, as represented in the force versus time graph. What is the velocity of the cart at t = 4.0 s?

A 2.0 kg cart moves along a straight, horizontal, frictionless track with an initial velocity of +2.0 m/s. Starting at time t = 0 s, a net horizontal force F is applied to the cart in the direction of its motion, as represented in the force versus time graph. What is the velocity of the cart at t = 4.0 s?

![A Cartesian graph with a horizontal axis labeled time t in seconds and a vertical axis labeled force F in newtons. The horizontal axis has labeled major grid lines and tick marks at integer values 0, 1, 2, 3, 4, 5. The vertical axis has labeled major grid lines and tick marks at integer values 0, 1, 2, 3, 4, 5, 6, 7. A single solid line begins at the origin (0, 0), extends with constant positive slope to a peak at (2, 6), and then extends with constant negative slope to touch the horizontal axis at (4, 0). From t = 4 to t = 5, the line remains at F = 0 along the horizontal axis. No other curves, shaded regions, text, or axes appear.](https://nerd-notes.com/wp-content/uploads/ubq-frq-generated/stem-fig-1-1787460166-tLSsIj.jpg)

- **A.** \(3.0\text{ m/s}\)
- **B.** \(5.0\text{ m/s}\)
- **C.** \(6.0\text{ m/s}\)
- **D.** \(8.0\text{ m/s}\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/120704/*