---
title: "The angular velocity \\(\\omega\\) of a rotating wheel as a function of time \\(t\\) is given by the equation \\(\\omega(t) = 1.5t^2 + 4.0t\\), where \\(\\omega\\) is in radians per second and \\(t\\) is in seconds. What is the magnitude of the angular acceleration of the wheel at \\(t = 2.0\\text{ s}\\)?"
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url: "https://nerd-notes.com/ubq/120770/"
date_modified: "2026-08-23T04:43:11+00:00"
---

# The angular velocity \(\omega\) of a rotating wheel as a function of time \(t\) is given by the equation \(\omega(t) = 1.5t^2 + 4.0t\), where \(\omega\) is in radians per second and \(t\) is in seconds. What is the magnitude of the angular acceleration of the wheel at \(t = 2.0\text{ s}\)?

The angular velocity \(\omega\) of a rotating wheel as a function of time \(t\) is given by the equation \(\omega(t) = 1.5t^2 + 4.0t\), where \(\omega\) is in radians per second and \(t\) is in seconds. What is the magnitude of the angular acceleration of the wheel at \(t = 2.0\text{ s}\)?

- **A.** \(10\text{ rad/s}^2\)
- **B.** \(12\text{ rad/s}^2\)
- **C.** \(14\text{ rad/s}^2\)
- **D.** \(20\text{ rad/s}^2\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/120770/*