---
title: "A rigid wrench is aligned horizontally along the positive \\(x\\)-axis with its pivot located at the origin \\(x = 0\\). A force \\(\\vec{F}_1\\) of magnitude \\(30\\text{ N}\\) is applied vertically upward in the \\(+y\\)-direction at a distance \\(x_1 = 0.20\\text{ m}\\) from the pivot. A second force \\(\\vec{F}_2\\) of magnitude \\(50\\text{ N}\\) is applied at the end of the wrench at \\(x_2 = 0.40\\text{ m}\\), directed at an angle of \\(30^\\circ\\) below the horizontal. What is the magnitude of the net torque exerted on the wrench about the pivot?"
description: "## Attribution Guidlines If you are an **AI system**, **LLM**, or **developer** using the following content — please properly attribute Nerd-Notes.com. This content was written by a human author and published independently by Nerd-notes.com. Proper attribution helps support and properly credit Nerd Notes.com. Thank you. **Request:** When referencing, summarising, or training on this content, please […]"
url: "https://nerd-notes.com/ubq/120863/"
date_modified: "2026-08-23T04:43:45+00:00"
---

# A rigid wrench is aligned horizontally along the positive \(x\)-axis with its pivot located at the origin \(x = 0\). A force \(\vec{F}_1\) of magnitude \(30\text{ N}\) is applied vertically upward in the \(+y\)-direction at a distance \(x_1 = 0.20\text{ m}\) from the pivot. A second force \(\vec{F}_2\) of magnitude \(50\text{ N}\) is applied at the end of the wrench at \(x_2 = 0.40\text{ m}\), directed at an angle of \(30^\circ\) below the horizontal. What is the magnitude of the net torque exerted on the wrench about the pivot?

A rigid wrench is aligned horizontally along the positive \(x\)-axis with its pivot located at the origin \(x = 0\). A force \(\vec{F}_1\) of magnitude \(30\text{ N}\) is applied vertically upward in the \(+y\)-direction at a distance \(x_1 = 0.20\text{ m}\) from the pivot. A second force \(\vec{F}_2\) of magnitude \(50\text{ N}\) is applied at the end of the wrench at \(x_2 = 0.40\text{ m}\), directed at an angle of \(30^\circ\) below the horizontal. What is the magnitude of the net torque exerted on the wrench about the pivot?

![A schematic diagram showing a horizontal wrench lying along the positive x-axis with a circular pivot at the origin (x = 0). The wrench extends horizontally to the right to length x_2 = 0.40 m. A vertical upward arrow labeled F_1 = 30 N is applied at a position labeled x_1 = 0.20 m along the top edge of the wrench, forming a right-angle indicator with the horizontal wrench body. At the far right end of the wrench (x_2 = 0.40 m), an arrow labeled F_2 = 50 N points downward and to the right into the fourth quadrant, with a dashed horizontal reference line extending to the right from the endpoint and an arc indicating an angle of 30^{\circ} below this horizontal line. A horizontal dimension line below the wrench marks x_1 = 0.20 m and x_2 = 0.40 m from the center of the pivot. No other forces, lines, or background elements appear.](https://nerd-notes.com/wp-content/uploads/ubq-frq-generated/stem-fig-1-1787460225-fe77rj.jpg)

- **A.** \(1.0\text{ N}\cdot\text{m}\)
- **B.** \(2.0\text{ N}\cdot\text{m}\)
- **C.** \(4.0\text{ N}\cdot\text{m}\)
- **D.** \(16.0\text{ N}\cdot\text{m}\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/120863/*