---
title: "A thin spherical shell of mass \\(0.60 \\text{ kg}\\) and radius \\(0.15 \\text{ m}\\) rolls without slipping along a horizontal surface with a constant translational speed of \\(2.0 \\text{ m/s}\\). The rotational inertia of the spherical shell about its center of mass is \\(I = \\dfrac{2}{3}MR^2\\). What is the rotational kinetic energy of the sphere?"
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date_modified: "2026-08-23T04:43:59+00:00"
---

# A thin spherical shell of mass \(0.60 \text{ kg}\) and radius \(0.15 \text{ m}\) rolls without slipping along a horizontal surface with a constant translational speed of \(2.0 \text{ m/s}\). The rotational inertia of the spherical shell about its center of mass is \(I = \dfrac{2}{3}MR^2\). What is the rotational kinetic energy of the sphere?

A thin spherical shell of mass \(0.60 \text{ kg}\) and radius \(0.15 \text{ m}\) rolls without slipping along a horizontal surface with a constant translational speed of \(2.0 \text{ m/s}\). The rotational inertia of the spherical shell about its center of mass is \(I = \dfrac{2}{3}MR^2\). What is the rotational kinetic energy of the sphere?

- **A.** \(0.80 \text{ J}\)
- **B.** \(1.2 \text{ J}\)
- **C.** \(1.6 \text{ J}\)
- **D.** \(2.0 \text{ J}\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/120874/*