---
title: "A small object of mass \\(0.50 \\text{ kg}\\) travels in the \\(xy\\)-plane with a constant velocity \\(\\vec{v} = (6.0 \\text{ m/s})\\hat{i}\\) along the line \\(y = 4.0 \\text{ m}\\). What is the magnitude of the angular momentum of the object relative to the origin \\((0,0)\\) at the instant the object passes through the point \\((3.0 \\text{ m}, 4.0 \\text{ m})\\)?"
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url: "https://nerd-notes.com/ubq/120900/"
date_modified: "2026-08-23T04:44:11+00:00"
---

# A small object of mass \(0.50 \text{ kg}\) travels in the \(xy\)-plane with a constant velocity \(\vec{v} = (6.0 \text{ m/s})\hat{i}\) along the line \(y = 4.0 \text{ m}\). What is the magnitude of the angular momentum of the object relative to the origin \((0,0)\) at the instant the object passes through the point \((3.0 \text{ m}, 4.0 \text{ m})\)?

A small object of mass \(0.50 \text{ kg}\) travels in the \(xy\)-plane with a constant velocity \(\vec{v} = (6.0 \text{ m/s})\hat{i}\) along the line \(y = 4.0 \text{ m}\). What is the magnitude of the angular momentum of the object relative to the origin \((0,0)\) at the instant the object passes through the point \((3.0 \text{ m}, 4.0 \text{ m})\)?

![A two-dimensional Cartesian coordinate system with a horizontal x-axis and a vertical y-axis intersecting at origin O. A horizontal dashed line is drawn parallel to the x-axis at y = 4.0 m. A point labeled P is located on this dashed line at coordinates (3.0 m, 4.0 m). An arrow pointing horizontally to the right from P is labeled with vector v. A solid straight line segment with an arrowhead extends from origin O to point P, representing position vector r. Axis tick marks indicate 0 and 3.0 m on the x-axis, and 0 and 4.0 m on the y-axis. No other labels, lines, text, or axes appear.](https://nerd-notes.com/wp-content/uploads/ubq-frq-generated/stem-fig-1-1787460251-0Ylg31.jpg)

- **A.** \(3.0 \text{ kg}\cdot\text{m}^2/\text{s}\)
- **B.** \(6.0 \text{ kg}\cdot\text{m}^2/\text{s}\)
- **C.** \(9.0 \text{ kg}\cdot\text{m}^2/\text{s}\)
- **D.** \(12 \text{ kg}\cdot\text{m}^2/\text{s}\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/120900/*