---
title: "A block attached to an ideal spring oscillates in simple harmonic motion along a horizontal, frictionless surface. A motion sensor records the position \\(x\\) of the block as a function of time \\(t\\), as shown in the graph. Based on the graph, what is the magnitude of the maximum acceleration of the block?"
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url: "https://nerd-notes.com/ubq/120966/"
date_modified: "2026-08-23T04:44:50+00:00"
---

# A block attached to an ideal spring oscillates in simple harmonic motion along a horizontal, frictionless surface. A motion sensor records the position \(x\) of the block as a function of time \(t\), as shown in the graph. Based on the graph, what is the magnitude of the maximum acceleration of the block?

A block attached to an ideal spring oscillates in simple harmonic motion along a horizontal, frictionless surface. A motion sensor records the position \(x\) of the block as a function of time \(t\), as shown in the graph. Based on the graph, what is the magnitude of the maximum acceleration of the block?

![A quantitative Cartesian graph of position \(x\) in meters versus time \(t\) in seconds. The horizontal axis is labeled \(t\text{ (s)}\) with numeric tick labels at 0, 1.0, 2.0, 3.0, and 4.0. The vertical axis is labeled \(x\text{ (m)}\) with numeric tick labels at -0.50, 0, and 0.50. Light gray gridlines align with each labeled tick mark and the half-second marks (0.5, 1.5, 2.5, 3.5). A single solid sinusoidal curve starts at the origin (0, 0), rises to a peak of 0.50 at \(t = 0.5\text{ s}\), crosses zero at \(t = 1.0\text{ s}\), reaches a trough of -0.50 at \(t = 1.5\text{ s}\), crosses zero at \(t = 2.0\text{ s}\), rises to a peak of 0.50 at \(t = 2.5\text{ s}\), crosses zero at \(t = 3.0\text{ s}\), reaches a trough of -0.50 at \(t = 3.5\text{ s}\), and returns to zero at \(t = 4.0\text{ s}\). No other lines, labels, arrows, or text appear.](https://nerd-notes.com/wp-content/uploads/ubq-frq-generated/stem-fig-1-1787460290-eXHTst.jpg)

- **A.** \(0.25\pi\text{ m/s}^2\)
- **B.** \(0.50\pi\text{ m/s}^2\)
- **C.** \(0.25\pi^2\text{ m/s}^2\)
- **D.** \(0.50\pi^2\text{ m/s}^2\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/120966/*