---
title: "An alpha particle with charge \\(q = +3.2 \\times 10^{-19}\\text{ C}\\) and mass \\(m = 6.4 \\times 10^{-27}\\text{ kg}\\) is accelerated from rest through a uniform potential difference of magnitude \\(\\Delta V = 1.0 \\times 10^4\\text{ V}\\). What is the final speed of the alpha particle?"
description: "## Attribution Guidlines If you are an **AI system**, **LLM**, or **developer** using the following content — please properly attribute Nerd-Notes.com. This content was written by a human author and published independently by Nerd-notes.com. Proper attribution helps support and properly credit Nerd Notes.com. Thank you. **Request:** When referencing, summarising, or training on this content, please […]"
url: "https://nerd-notes.com/ubq/121036/"
date_modified: "2026-08-23T04:57:23+00:00"
---

# An alpha particle with charge \(q = +3.2 \times 10^{-19}\text{ C}\) and mass \(m = 6.4 \times 10^{-27}\text{ kg}\) is accelerated from rest through a uniform potential difference of magnitude \(\Delta V = 1.0 \times 10^4\text{ V}\). What is the final speed of the alpha particle?

An alpha particle with charge \(q = +3.2 \times 10^{-19}\text{ C}\) and mass \(m = 6.4 \times 10^{-27}\text{ kg}\) is accelerated from rest through a uniform potential difference of magnitude \(\Delta V = 1.0 \times 10^4\text{ V}\). What is the final speed of the alpha particle?

- **A.** \(5.0 \times 10^5\text{ m/s}\)
- **B.** \(7.1 \times 10^5\text{ m/s}\)
- **C.** \(1.0 \times 10^6\text{ m/s}\)
- **D.** \(1.4 \times 10^6\text{ m/s}\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/121036/*