---
title: "A proton of mass \\(m\\) and charge \\(+e\\) and an alpha particle of mass \\(4m\\) and charge \\(+2e\\) are each released from rest and accelerated through the same electric potential difference \\(\\Delta V\\). What is the ratio of the final momentum of the alpha particle to that of the proton, \\(\\dfrac{p_\\alpha}{p_p}\\)?"
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url: "https://nerd-notes.com/ubq/121037/"
date_modified: "2026-08-23T04:57:26+00:00"
---

# A proton of mass \(m\) and charge \(+e\) and an alpha particle of mass \(4m\) and charge \(+2e\) are each released from rest and accelerated through the same electric potential difference \(\Delta V\). What is the ratio of the final momentum of the alpha particle to that of the proton, \(\dfrac{p_\alpha}{p_p}\)?

A proton of mass \(m\) and charge \(+e\) and an alpha particle of mass \(4m\) and charge \(+2e\) are each released from rest and accelerated through the same electric potential difference \(\Delta V\). What is the ratio of the final momentum of the alpha particle to that of the proton, \(\dfrac{p_\alpha}{p_p}\)?

- **A.** \(\dfrac{1}{\sqrt{2}}\)
- **B.** \(2\)
- **C.** \(2\sqrt{2}\)
- **D.** \(8\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/121037/*