---
title: "A student prepares a saturated solution of silver chromate, \\(\\text{Ag}_2\\text{CrO}_4(s)\\), by adding excess solid to a \\(0.050\\text{ M }\\text{K}_2\\text{CrO}_4(aq)\\) solution at \\(298\\text{ K}\\). The dissolution equilibrium and solubility product constant, \\(K_{sp}\\), are represented below.  \\[\\text{Ag}_2\\text{CrO}_4(s) \\rightleftharpoons 2\\,\\text{Ag}^+(aq) + \\text{CrO}_4^{2-}(aq) \\quad K_{sp} = 2.0 \\times 10^{-11}\\text{ at }298\\text{ K}\\]  Assuming the change in volume upon adding the solid is negligible, what is the molar solubility of \\(\\text{Ag}_2\\text{CrO}_4\\) in the \\(0.050\\text{ M }\\text{K}_2\\text{CrO}_4(aq)\\) solution at \\(298\\text{ K}\\)?"
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date_modified: "2026-08-23T05:02:06+00:00"
---

# A student prepares a saturated solution of silver chromate, \(\text{Ag}_2\text{CrO}_4(s)\), by adding excess solid to a \(0.050\text{ M }\text{K}_2\text{CrO}_4(aq)\) solution at \(298\text{ K}\). The dissolution equilibrium and solubility product constant, \(K_{sp}\), are represented below.

\[\text{Ag}_2\text{CrO}_4(s) \rightleftharpoons 2\,\text{Ag}^+(aq) + \text{CrO}_4^{2-}(aq) \quad K_{sp} = 2.0 \times 10^{-11}\text{ at }298\text{ K}\]

Assuming the change in volume upon adding the solid is negligible, what is the molar solubility of \(\text{Ag}_2\text{CrO}_4\) in the \(0.050\text{ M }\text{K}_2\text{CrO}_4(aq)\) solution at \(298\text{ K}\)?

A student prepares a saturated solution of silver chromate, \(\text{Ag}_2\text{CrO}_4(s)\), by adding excess solid to a \(0.050\text{ M }\text{K}_2\text{CrO}_4(aq)\) solution at \(298\text{ K}\). The dissolution equilibrium and solubility product constant, \(K_{sp}\), are represented below.

\[\text{Ag}_2\text{CrO}_4(s) \rightleftharpoons 2\,\text{Ag}^+(aq) + \text{CrO}_4^{2-}(aq) \quad K_{sp} = 2.0 \times 10^{-11}\text{ at }298\text{ K}\]

Assuming the change in volume upon adding the solid is negligible, what is the molar solubility of \(\text{Ag}_2\text{CrO}_4\) in the \(0.050\text{ M }\text{K}_2\text{CrO}_4(aq)\) solution at \(298\text{ K}\)?

- **A.** \(1.0 \times 10^{-5}\text{ M}\)
- **B.** \(2.0 \times 10^{-5}\text{ M}\)
- **C.** \(4.0 \times 10^{-5}\text{ M}\)
- **D.** \(2.0 \times 10^{-4}\text{ M}\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/121404/*
