---
title: "A student prepares a standard solution using a stock solution of \\(0.400\\text{ M }\\text{Cu(NO}_3\\text{)}_2\\text{(aq)}\\). First, the student uses a volumetric pipet to transfer a \\(10.0\\text{ mL}\\) aliquot of the stock solution into a \\(100.0\\text{ mL}\\) volumetric flask and adds distilled water to the calibration mark, producing Solution 1. Next, the student transfers a \\(25.0\\text{ mL}\\) sample of Solution 1 into a beaker and adds \\(75.0\\text{ mL}\\) of distilled water, assuming volumes are additive. What is the molar concentration of nitrate ions, \\([\\text{NO}_3^-]\\), in the final mixture?"
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url: "https://nerd-notes.com/ubq/123672/"
date_modified: "2026-09-28T12:01:57+00:00"
---

# A student prepares a standard solution using a stock solution of \(0.400\text{ M }\text{Cu(NO}_3\text{)}_2\text{(aq)}\). First, the student uses a volumetric pipet to transfer a \(10.0\text{ mL}\) aliquot of the stock solution into a \(100.0\text{ mL}\) volumetric flask and adds distilled water to the calibration mark, producing Solution 1. Next, the student transfers a \(25.0\text{ mL}\) sample of Solution 1 into a beaker and adds \(75.0\text{ mL}\) of distilled water, assuming volumes are additive. What is the molar concentration of nitrate ions, \([\text{NO}_3^-]\), in the final mixture?

A student prepares a standard solution using a stock solution of \(0.400\text{ M }\text{Cu(NO}_3\text{)}_2\text{(aq)}\). First, the student uses a volumetric pipet to transfer a \(10.0\text{ mL}\) aliquot of the stock solution into a \(100.0\text{ mL}\) volumetric flask and adds distilled water to the calibration mark, producing Solution 1. Next, the student transfers a \(25.0\text{ mL}\) sample of Solution 1 into a beaker and adds \(75.0\text{ mL}\) of distilled water, assuming volumes are additive. What is the molar concentration of nitrate ions, \([\text{NO}_3^-]\), in the final mixture?

- **A.** \(1.00 \times 10^{-2}\text{ M}\)
- **B.** \(2.00 \times 10^{-2}\text{ M}\)
- **C.** \(4.00 \times 10^{-2}\text{ M}\)
- **D.** \(8.00 \times 10^{-2}\text{ M}\)

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