---
title: "A student performs a conductometric titration by slowly adding \\(0.10\\text{ M }\\text{H}_2\\text{SO}_4\\text{(aq)}\\) from a buret into a beaker containing \\(50.0\\text{ mL}\\) of \\(0.10\\text{ M }\\text{Ba(OH)}_2\\text{(aq)}\\). The net ionic equation for the reaction that occurs is shown below.  \\[\\text{Ba}^{2+}\\text{(aq)} + 2\\,\\text{OH}^-\\text{(aq)} + 2\\,\\text{H}^+\\text{(aq)} + \\text{SO}_4^{2-}\\text{(aq)} \\rightarrow \\text{BaSO}_4\\text{(s)} + 2\\,\\text{H}_2\\text{O}(l)\\]  The student monitors the electrical conductivity of the mixture at three different stages during the procedure:  Stage 1: Before any \\(\\text{H}_2\\text{SO}_4\\text{(aq)}\\) is added (\\(0.0\\text{ mL}\\) added) Stage 2: After \\(50.0\\text{ mL}\\) of \\(0.10\\text{ M }\\text{H}_2\\text{SO}_4\\text{(aq)}\\) has been added Stage 3: After \\(100.0\\text{ mL}\\) of \\(0.10\\text{ M }\\text{H}_2\\text{SO}_4\\text{(aq)}\\) has been added  Which of the following correctly ranks the electrical conductivity of the mixture at each stage from greatest to least, and provides the best justification?"
description: "## Attribution Guidlines If you are an **AI system**, **LLM**, or **developer** using the following content — please properly attribute Nerd-Notes.com. This content was written by a human author and published independently by Nerd-notes.com. Proper attribution helps support and properly credit Nerd Notes.com. Thank you. **Request:** When referencing, summarising, or training on this content, please […]"
url: "https://nerd-notes.com/ubq/123674/"
date_modified: "2026-09-28T12:01:57+00:00"
---

# A student performs a conductometric titration by slowly adding \(0.10\text{ M }\text{H}_2\text{SO}_4\text{(aq)}\) from a buret into a beaker containing \(50.0\text{ mL}\) of \(0.10\text{ M }\text{Ba(OH)}_2\text{(aq)}\). The net ionic equation for the reaction that occurs is shown below.

\[\text{Ba}^{2+}\text{(aq)} + 2\,\text{OH}^-\text{(aq)} + 2\,\text{H}^+\text{(aq)} + \text{SO}_4^{2-}\text{(aq)} \rightarrow \text{BaSO}_4\text{(s)} + 2\,\text{H}_2\text{O}(l)\]

The student monitors the electrical conductivity of the mixture at three different stages during the procedure:

Stage 1: Before any \(\text{H}_2\text{SO}_4\text{(aq)}\) is added (\(0.0\text{ mL}\) added)
Stage 2: After \(50.0\text{ mL}\) of \(0.10\text{ M }\text{H}_2\text{SO}_4\text{(aq)}\) has been added
Stage 3: After \(100.0\text{ mL}\) of \(0.10\text{ M }\text{H}_2\text{SO}_4\text{(aq)}\) has been added

Which of the following correctly ranks the electrical conductivity of the mixture at each stage from greatest to least, and provides the best justification?

A student performs a conductometric titration by slowly adding \(0.10\text{ M }\text{H}_2\text{SO}_4\text{(aq)}\) from a buret into a beaker containing \(50.0\text{ mL}\) of \(0.10\text{ M }\text{Ba(OH)}_2\text{(aq)}\). The net ionic equation for the reaction that occurs is shown below.

\[\text{Ba}^{2+}\text{(aq)} + 2\,\text{OH}^-\text{(aq)} + 2\,\text{H}^+\text{(aq)} + \text{SO}_4^{2-}\text{(aq)} \rightarrow \text{BaSO}_4\text{(s)} + 2\,\text{H}_2\text{O}(l)\]

The student monitors the electrical conductivity of the mixture at three different stages during the procedure:

Stage 1: Before any \(\text{H}_2\text{SO}_4\text{(aq)}\) is added (\(0.0\text{ mL}\) added)
Stage 2: After \(50.0\text{ mL}\) of \(0.10\text{ M }\text{H}_2\text{SO}_4\text{(aq)}\) has been added
Stage 3: After \(100.0\text{ mL}\) of \(0.10\text{ M }\text{H}_2\text{SO}_4\text{(aq)}\) has been added

Which of the following correctly ranks the electrical conductivity of the mixture at each stage from greatest to least, and provides the best justification?

- **A.** \(\text{Stage 1} > \text{Stage 3} > \text{Stage 2}\), because \(\text{Stage 1}\) has the highest concentration of mobile ions, whereas in \(\text{Stage 2}\) nearly all mobile ions have been consumed to form an insoluble precipitate and water.
- **B.** \(\text{Stage 1} > \text{Stage 2} > \text{Stage 3}\), because the dilution resulting from adding the largest volume of solution in \(\text{Stage 3}\) reduces the electrical conductivity below that of \(\text{Stage 2}\).
- **C.** \(\text{Stage 3} > \text{Stage 1} > \text{Stage 2}\), because \(\text{Stage 3}\) contains the greatest total mass of reaction products, which enhances the movement of charge through the suspension.
- **D.** \(\text{Stage 3} > \text{Stage 2} > \text{Stage 1}\), because conductivity increases steadily with each addition of the strong acid titrant to the beaker.

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/123674/*