---
title: "A gaseous compound, \\(\\text{XY}_3\\text{(g)}\\), undergoes a first-order decomposition in a rigid, sealed container at constant temperature according to the balanced equation below.  \\[ 2\\text{XY}_3\\text{(g)} \\rightarrow \\text{X}_2\\text{(g)} + 3\\text{Y}_2\\text{(g)} \\]  The rate constant for this reaction at the operating temperature is \\(k = 2.31 \\times 10^{-4}\\text{ s}^{-1}\\). If the reaction begins with pure \\(\\text{XY}_3\\text{(g)}\\) at an initial partial pressure of \\(1.60\\text{ atm}\\), what is the partial pressure of \\(\\text{Y}_2\\text{(g)}\\) in the container after \\(6000\\text{ s}\\)?"
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url: "https://nerd-notes.com/ubq/123684/"
date_modified: "2026-09-28T12:01:58+00:00"
---

# A gaseous compound, \(\text{XY}_3\text{(g)}\), undergoes a first-order decomposition in a rigid, sealed container at constant temperature according to the balanced equation below.

\[ 2\text{XY}_3\text{(g)} \rightarrow \text{X}_2\text{(g)} + 3\text{Y}_2\text{(g)} \]

The rate constant for this reaction at the operating temperature is \(k = 2.31 \times 10^{-4}\text{ s}^{-1}\). If the reaction begins with pure \(\text{XY}_3\text{(g)}\) at an initial partial pressure of \(1.60\text{ atm}\), what is the partial pressure of \(\text{Y}_2\text{(g)}\) in the container after \(6000\text{ s}\)?

A gaseous compound, \(\text{XY}_3\text{(g)}\), undergoes a first-order decomposition in a rigid, sealed container at constant temperature according to the balanced equation below.

\[ 2\text{XY}_3\text{(g)} \rightarrow \text{X}_2\text{(g)} + 3\text{Y}_2\text{(g)} \]

The rate constant for this reaction at the operating temperature is \(k = 2.31 \times 10^{-4}\text{ s}^{-1}\). If the reaction begins with pure \(\text{XY}_3\text{(g)}\) at an initial partial pressure of \(1.60\text{ atm}\), what is the partial pressure of \(\text{Y}_2\text{(g)}\) in the container after \(6000\text{ s}\)?

- **A.** \(0.60\text{ atm}\)
- **B.** \(1.20\text{ atm}\)
- **C.** \(1.80\text{ atm}\)
- **D.** \(2.80\text{ atm}\)

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/123684/*