---
title: "A student titrates a \\(25.0 \\text{ mL}\\) sample of \\(0.10 \\text{ M } \\text{CH}_3\\text{COOH(aq)}\\) with \\(0.10 \\text{ M } \\text{NaOH(aq)}\\). In a second experiment, the student titrates an identical \\(25.0 \\text{ mL}\\) sample of \\(0.10 \\text{ M } \\text{CH}_3\\text{COOH(aq)}\\) using \\(0.20 \\text{ M } \\text{NaOH(aq)}\\). Which of the following correctly predicts the volume of titrant required to reach the equivalence point and the \\(\\text{pH}\\) at the equivalence point in the second titration compared to the first titration?"
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url: "https://nerd-notes.com/ubq/123771/"
date_modified: "2026-09-28T12:30:15+00:00"
---

# A student titrates a \(25.0 \text{ mL}\) sample of \(0.10 \text{ M } \text{CH}_3\text{COOH(aq)}\) with \(0.10 \text{ M } \text{NaOH(aq)}\). In a second experiment, the student titrates an identical \(25.0 \text{ mL}\) sample of \(0.10 \text{ M } \text{CH}_3\text{COOH(aq)}\) using \(0.20 \text{ M } \text{NaOH(aq)}\). Which of the following correctly predicts the volume of titrant required to reach the equivalence point and the \(\text{pH}\) at the equivalence point in the second titration compared to the first titration?

A student titrates a \(25.0 \text{ mL}\) sample of \(0.10 \text{ M } \text{CH}_3\text{COOH(aq)}\) with \(0.10 \text{ M } \text{NaOH(aq)}\). In a second experiment, the student titrates an identical \(25.0 \text{ mL}\) sample of \(0.10 \text{ M } \text{CH}_3\text{COOH(aq)}\) using \(0.20 \text{ M } \text{NaOH(aq)}\). Which of the following correctly predicts the volume of titrant required to reach the equivalence point and the \(\text{pH}\) at the equivalence point in the second titration compared to the first titration?

- **A.** The volume of \(\text{NaOH(aq)}\) required is halved, and the \(\text{pH}\) at the equivalence point is lower because less total volume of base is added to the flask.
- **B.** The volume of \(\text{NaOH(aq)}\) required is doubled, and the \(\text{pH}\) at the equivalence point is higher because the base solution is more concentrated.
- **C.** The volume of \(\text{NaOH(aq)}\) required is halved, and the \(\text{pH}\) at the equivalence point is higher because the smaller total solution volume results in a higher concentration of \(\text{CH}_3\text{COO}^-\).
- **D.** The volume of \(\text{NaOH(aq)}\) required is unchanged, and the \(\text{pH}\) at the equivalence point is higher because the strong base reacts more extensively with the weak acid.

*The answer key and step-by-step explanation are available to logged-in users at https://nerd-notes.com/ubq/123771/*